编码/雨燕为(6.1的Xcode)解码枚举
问题描述:
var priority : Priority! = Priority.defaultPriority
func encodeWithCoder(aCoder: NSCoder) {
aCoder.encodeInteger(priority.toRaw(), forKey: "priority") //toRaw may not yield the result I am expecting
}
required init(coder aDecoder: NSCoder) {
priority = aDecoder.decodeIntegerForKey("priority") //complaining about conflicting types
}
与枚举为以下几点:
enum Priority : Int {
case defaultPriority = 0
case lowPriority = 1
case mediumPriority = 2
case highPriority = 3
}
什么是编码的最好方法/解码呢?
答
Priority.init(rawValue:)
应该工作。
func encodeWithCoder(aCoder: NSCoder) {
aCoder.encodeInteger(priority.rawValue, forKey: "priority")
}
required init(coder aDecoder: NSCoder) {
priority = Priority(rawValue: aDecoder.decodeIntegerForKey("priority"))
}
+1
感谢您为6.1添加更新。 – jpittman 2014-10-21 07:00:46
+0
非常感谢您的帮助。 – Aaronium112 2016-07-09 18:10:00
相似问题:http://stackoverflow.com/questions/26326645/how-do-i-encode-enum-using-nscoder-in-swift。 – 2014-10-18 08:59:39