XML属性c＃

Question

我需要显示processingStatus和每个字段节点值及其相应的以下XML名称。

<?xml version="1.0" encoding="UTF-8"?> 
<T24 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.temenos.com/T24/OFSML/130" xsi:schemaLocation="http://www.temenos.com/T24/OFSML/130 ofsml13.xsd"> 
    <serviceResponse> 
    <ofsTransactionProcessed application="FUNDS.TRANSFER" function="INPUT" operation="VALIDATE" processingStatus="OK" version="BOOK.TRAN.VAL.MCB"> 
     <transactionId>FT15056T2QLP</transactionId> 
     <field mv="1" name="TRANSACTION.TYPE" sv="1">AC</field> 
     <field mv="1" name="CURRENCY.MKT.DR" sv="1">1</field> 
     <field mv="1" name="DEBIT.CURRENCY" sv="1">USD</field> 
     <field mv="1" name="DEBIT.AMOUNT" sv="1">125.00</field> 
     <field mv="1" name="DEBIT.VALUE.DATE" sv="1">20150225</field> 

    </ofsTransactionProcessed> 
    </serviceResponse> 
</T24> 

任何人都可以帮助我吗？ 我的代码： 编辑的代码：

XmlTextReader reader = new XmlTextReader("XML03.xml"); 
      Console.WriteLine(reader.Attributes["processingStatus"].Value); 
      while (reader.Read()) 
      { 
       Console.WriteLine(reader.Value); 

      } 
      Console.ReadLine(); 

Answer 1

一种可能性是定义一个类型或多种类型反映了XML的结构;成员必须被赋予属于XmlElementAttribute的属性here和属性XmlAttributeAttribute，其被记录为here;如果合适，文件内容可以使用XmlDeserializer类进行反序列化，该类记录为here。有关如何使用反序列化设施的详细说明，请参见this官方教程。

Answer 2

尝试XML LINQ

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Xml; 
using System.Xml.Linq; 

namespace ConsoleApplication1 
{ 
    class Program 
    { 
     const string FILENAME = @"c:\temp\test.xml"; 
     static void Main(string[] args) 
     { 
      XDocument doc = XDocument.Load(FILENAME); 
      var results = doc.Descendants().Where(x => x.Name.LocalName == "ofsTransactionProcessed").Select(x => new { 
       application = (string)x.Attribute("application"), 
       function = (string)x.Attribute("function"), 
       operation = (string)x.Attribute("operation"), 
       processingStatus = (string)x.Attribute("processingStatus"), 
       version = (string)x.Attribute("version"), 
       transactionId = x.Elements().Where(y => y.Name.LocalName == "transactionId").Select(z => (string)z).FirstOrDefault(), 
       fields = x.Elements().Where(y => y.Name.LocalName == "field").Select(z => new { 
        mv = (string)z.Attribute("mv"), 
        name = (string)z.Attribute("name"), 
        sv = (string)z.Attribute("sv"), 
        value = (string)z 
       }).ToList() 
      }).FirstOrDefault(); 
     } 
    } 
}