searchByEmail方法不起作用

Question

我有这个方法的问题。当用户请求时，它不输出正确的搜索。

这里是我的代码：

System.out.println("Search by Email."); 
Employee employeeSearchEmail = MenuMethods.userInputByEmail(); 
Store.searchByEmail(employeeSearchEmail.getEmployeeEmail()); 

public Employee searchByEmail(String employeeEmail) { 
    for (Employee employee : map.values()) { 
     System.out.println(employee); 
     map.equals(getClass()); 
     map.equals(employee.getEmployeeEmail()); 
     employee = new Employee(employeeEmail); 
     ; 
     return employee; 
    } 
    return null; 
} 

public static Employee userInputByEmail() { 
    // String temp is for some reason needed. If it is not included 
    // The code will not execute properly. 
    String temp = keyboard.nextLine(); 
    Employee e = null; 
    System.out.println("Please enter the Employee Email:"); 
    String employeeEmail = keyboard.nextLine(); 
    // This can use the employeeName's constructor because java accepts the 
    // parameters instead 
    // of the name's. 
    return e = new Employee(employeeEmail); 

} 

Answer 1

的问题是，有没有条件，如果在你的程序是这样的：

public Employee searchByEmail(String employeeEmail) { 
     for (Employee employee : map.values()) { 
      map.equals(getClass()); 
      if (map.equals(employee.getEmployeeEmail())){ 
       System.out.println(employee); 
       return employee; 
      } 
     } 
     return null; 
    } 

这一行： 的System.out.println （雇员）;

，直到找到了比赛，当比赛将返回该员工的对象..

Answer 2

你应该这样说

if(employeeEmail.equals(employee.getEmployeeEmail()) return employee; 

没有必要创建Employee对象的新实例。

Answer 3

您想要返回具有特定电子邮件地址的员工。

public Employee searchByEmail(String employeeEmail) 
    { 
      for(Employee employee : map.values()) 
      { 
       if(employee.getEmployeeEmail().equalsIgnoreCase(employeeEmail.trim())) 
          return employee; 
      } 
      return null; 
    } 

顺便说一句，什么是地图的键：因此，如果当前员工的电子邮件地址，等于给定的电子邮件地址，你应该只返回。如果电子邮件地址的关键是，你可以简单地返回：

return map.get(employeeEmail);