如何在筛选器中获取筛选器httpservletresponse outputstream错误消息

Question

我使用spring 4和筛选器我在servletResponse中得到了一些错误响应。它包含带有错误消息的outputstream。 如何在输出流中获取此错误消息并审核到我的应用程序？

try{    
      filterChain.doFilter(wrappedRequest, servletResponse); 
      HttpServletResponse httpServletResponse = (HttpServletResponse) servletResponse; 
      LOGGER.info("Basic Authenticate HttpServletResponse code {}"+httpServletResponse.getStatus()); 

      httpServletResponse.getOutputStream(); 
// I need to read this outputstream, its contains error message.? 




    }catch(Exception e){ 
     LOGGER.error("Error Basic Authenticate Error :{}", e); 
     HttpServletResponse httpServletResponse = (HttpServletResponse) servletResponse; 
     AtomicInteger statusCode = new AtomicInteger(httpServletResponse.getStatus()); 
     Response response = ResponseUtil.populateResponse(statusCode, e.getMessage().toString(), 0); 
     httpServletResponse.sendError(httpServletResponse.getStatus(), e.getMessage()); 
     auditService.updateRestAuditRecord(auditId,StringUtils.EMPTY, response); 
    } 

Answer 1

关键是装饰者类HttpServletResponseWrapper。根据您的具体需求调整这些步骤：

1. 完全读取您想审核的流类似于字节缓冲区。
2. 做你的审计任务。
3. 扩展HttpServletResponseWrapper，覆盖getOutputStream()并返回一个扩展名为ServletOutputStream的扩展字节缓冲区。
4. 将HttpServletResponseWrapper传递给链中的下一个下游过滤器。