从手机的电话目录中检索联系人
问题描述:
此代码可以在移动设备上打开内置联系人目录。但是,当我选择联系人时,应用报告“完成”,但不检索联系人号码 - 用户无法发送消息。从手机的电话目录中检索联系人
如何检索联系电话号码? List View
不是解决方案:我需要返回一个数字,而不是额外的信息。
这里是我的代码:
public EditText no;
public EditText msg;
public Button cancel;
public Button snd;
public String Number,name,Message;
public int run=0;
public static final int PICK_CONTACT=1;
public void callContacts(View v)
{
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent,PICK_CONTACT);
}
@Override
public void onActivityResult(int reqCode,int resultCode,Intent data)
{
super.onActivityResult(reqCode,resultCode,data);
if(reqCode==PICK_CONTACT)
{
if(resultCode== ActionBarActivity.RESULT_OK)
{
Uri contactData = data.getData();
Cursor c = getContentResolver().query(contactData,null,null,null,null);
if(c.moveToFirst())
{
name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.CONTENT_URI.toString()));
Toast.makeText(this,"done",Toast.LENGTH_SHORT).show();
}
}
}
}
这里是onCreate
方法
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_second);
no = (EditText)findViewById(R.id.num);
msg = (EditText)findViewById(R.id.sms);
cancel = (Button)findViewById(R.id.cancel);
snd = (Button)findViewById(R.id.snd);
no.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
msg.setText("");
no.setText("");
callContacts(null);
}
});
snd.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View v)
{
Number = no.toString();
Message = msg.getText().toString();
SmsManager manager = SmsManager.getDefault();
ArrayList<String>long_sms = manager.divideMessage(Message);
manager.sendMultipartTextMessage(Number,null,long_sms,null,null);
Toast.makeText(getApplicationContext(),"Sent Successfully",Toast.LENGTH_SHORT).show();
}
});
}
答
这里只是从联系人列表中选择一个电话号码的代码。我发现这个代码最简单。让我知道是否有任何问题。与手机的数据类型选秀意图
开始活动:
findViewById(R.id.choose_contact_button).setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent pickContact = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(pickContact, PICK_CONTACT_REQUEST);
}
});
现在设置onAcitivityResult();
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent intent){
switch (requestCode){
case PICK_CONTACT_REQUEST:
if (resultCode == RESULT_OK){
Uri contactUri = intent.getData();
Cursor nameCursor = getContentResolver().query(contactUri, null, null, null, null);
if (nameCursor.moveToFirst()){
String name = nameCursor.getString(nameCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String number = nameCursor.getString(nameCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
((EditText)findViewById(R.id.person_name)).setText(name);
((EditText)findViewById(R.id.enter_mobile)).setText(number);
nameCursor.close();
}
}
break;
}
}
加紧措辞;正确的语法。 – Prune
[从android应用中的联系人列表中选择号码和姓名]的可能重复(http://stackoverflow.com/questions/9496350/pick-a-number-and-name-from-contacts-list-in-android- APP) – Bryan