这个PHP脚本有什么问题

Question

嘿，我正在一个简单的注册表单上工作，我已经做了一个简单的测试。基本上我说如果提交的用户名是空的，我们点击提交它会回显'所有的字段是必需的'否则好吧。我的代码看起来很好，否则我要去疯能有一个人看看我谢谢:)

CODE：

<?php 

    //require 'core.inc.php'; 



if(isset($_POST['username'])&& isset($_POST['password']) && isset($_POST['passwordAgain'])&& isset($_POST['Firstname'])&& isset($_POST['Lastname'])){ 

    $username = $_POST['username']; 
    $password = $_POST['password']; 
    $password_again = $_POST['passwordAgain']; 
    $Firstname = $_POST['Firstname']; 
    $Lastname = $_POST['Lastname']; 

    if(!empty($username)){ 

     echo 'OK.'; 

    }else{ 

    echo 'fill in all details thank you'; 
    } 


} 

?> 


<form action="join.inc.php" method="POST"> 


    Username: <input type="text" name="username" /><br /> 
    Password: <input type="password" type="password" /><br /> 
    Password Again: <input type="password" type="passwordAgain" /><br /> 
    FirstName: <input type="text" name ="Firstname"/><br /> 
    LastName: <input type="text" name ="Lastname" /><br /> 
    <input type="submit" value="SUBMIT" /> 
</form> 

Answer 1

纠正这个：

Password: <input type="password" name="password" /><br /> 
Password Again: <input type="password" name="passwordAgain" /><br /> 

Answer 2

你的问题是你的HTML：

Password: <input type="password" type="password" /><br /> 
Password Again: <input type="password" type="passwordAgain" /><br /> 

您指定类型的字段，而不是两倍的名称字段。

Answer 3

什么提交按钮，并尝试这样给名字：

<input type="submit" name="sbmtBtn" value="SUBMIT" /> 

，并提交部分为：

if(isset($_POST['sbmtBtn'])) 
{ 

$username = $_POST['username']; 
$password = $_POST['password']; 
$password_again = $_POST['passwordAgain']; 
$Firstname = $_POST['Firstname']; 
$Lastname = $_POST['Lastname']; 

if($username && $password && $password_again && $Firstname && $Lastname)) 
{ 

    echo 'OK.'; 

} 
else 
{ 

    echo 'all fields are required.'; 
} 


}