更改Javascript变量不刷新
问题描述:
我想知道如何去改变JavaScript中的“image.src”而不刷新页面(以及没有清除画布)。更改Javascript变量不刷新
我在想使用像AJAX这样的东西(我从来没有用过它),但我不确定这是否是正确的路径。任何人都可以帮我吗?
这里是我的代码:
<form>
Image URL:<input type="text" size="50" name="i" value="<?php echo $_REQUEST['i']?>" />
Background Color:<select name="color" >
<?php if($_REQUEST['color'] == "#000000"){ ?>
<option value="#000000">Black</option>
<option value="#ffffff">White</option>
<?php }else{ ?>
<option value="#ffffff">White</option>
<option value="#000000">Black</option>
<?php } ?>
</select>
<input type="submit"/> || Back to the <a href="/cloner/index.php">Home Page</a>
</form>
</div>
<script type="text/javascript">
var imageWidthHalf, imageHeightHalf;
var canvas = document.createElement('canvas');
var height = window.innerHeight;
canvas.width = window.innerWidth;
canvas.height = height;
canvas.style.display = 'block';
document.body.appendChild(canvas);
var context = canvas.getContext('2d');
var image = document.createElement('img');
image.addEventListener('load', function() {
imageWidthHalf = Math.floor(this.width/2);
imageHeightHalf = Math.floor(this.height/2);
document.addEventListener('mousemove', onMouseEvent, false);
document.addEventListener('touchstart', onTouchEvent, false);
document.addEventListener('touchmove', onTouchEvent, false);
}, false);
image.src = "<?php echo $_REQUEST['i']; ?>";
function onMouseEvent(event) {
context.drawImage(image, event.clientX - imageWidthHalf, event.clientY - '50' - imageHeightHalf);
}
function onTouchEvent(event) {
event.preventDefault();
for (var i = 0; i < event.touches.length; i++) {
context.drawImage(image, event.touches[i].pageX - imageWidthHalf, event.touches[i].pageY - imageHeightHalf);
}
}
</script>
答
document.querySelector('input[name="i"]').addEventListener('blur', function() {
image.src = this.value;
}, false);
,如果你可以让我编辑您的代码,以便它会更好看 – ianace 2012-01-01 04:06:35
你要什么的'img.src'改变?如果在网页的JavaScript中知道该URL,则只需设置“img.src = url”即可。如果您必须从服务器获取URL,那么您将使用ajax调用来获取URL,然后分配'img.src'。 – jfriend00 2012-01-01 04:11:47
@ianace如果你必须,但我alreayd下面从约瑟夫西尔伯答案。 – Alice 2012-01-01 04:46:28