无法获取位图从谷歌个人资料图片url

问题描述：

我有一个应用程序，我试图从我通过谷歌整合获得的链接检索图像。但是，每当我尝试将图片转化为位图时，它总会给我一个错误。代码和错误是下面：无法获取位图从谷歌个人资料图片url

代码：

if (google_user_gallery_pic.isEmpty() == true) 
{ 
    if (google_user_pic.isEmpty() == false) 
    { 
     onPost = null; 
     onPost2 = null; 
     onPost = getBitmapFromURL(google_user_pic); 
     onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 

    else 
    { 
     onPost = null; 
     onPost2 = null; 
     onPost = BitmapFactory.decodeFile(google_user_gallery_pic); 
     if (onPost == null) 
     { 
      onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson); 
     } 

     else 
     { 
      onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
     } 
    } 
} 

else 
{ 
    onPost = null; 
    onPost2 = null; 
    onPost = BitmapFactory.decodeFile(google_user_gallery_pic); 
    if (onPost == null) 
    { 
     onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson); 
     //onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 

    else 
    { 
     onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 
}

错误：

E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: https:/lh3.googleusercontent.com/-HW5Tk9h1V2I/AAAAAAAAAAI/AAAAAAAADA8/7UbMeHbyFLM/photo.jpg: open failed: ENOENT (No such file or directory)

的网址：

https://lh3.googleusercontent.com/-HW5Tk9h1V2I/AAAAAAAAAAI/AAAAAAAADA8/7UbMeHbyFLM/photo.jpg

此网址工作一个页面，但不工作对另一个。这两个页面都是片段活动。任何帮助将不胜感激，谢谢！

为什么不使用毕加索：

private Target mTarget; //declare variable void loadImage(Context context, String url) { final ImageView imageView = (ImageView) findViewById(R.id.image); mTarget = new Target() { @Override public void onBitmapLoaded (final Bitmap bitmap, Picasso.LoadedFrom from){ //Do something on the bitmap imageView.setImageBitmap(bitmap); //set the bitmap } @Override public void onBitmapFailed(Drawable errorDrawable) { } @Override public void onPrepareLoad(Drawable placeHolderDrawable) { } }; Picasso.with(context) .load(url) .into(mTarget); ..error(R.drawable.the_smallperson) // will be displayed if the image cannot be loaded }

的gradle中添加

？ – rafsanahmad007

@ rafsanahmad007 idk如何使用 –

您是否将位图保存在文件中并尝试打开它？ – rafsanahmad007

答

尝试扭转if和else条件是这样的：

if (google_user_gallery_pic.isEmpty() == false) 
{ 
    if (google_user_pic.isEmpty() == false) 
    { 
     onPost = null; 
     onPost2 = null; 
     onPost = getBitmapFromURL(google_user_pic); 
     onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 

    else 
    { 
     onPost = null; 
     onPost2 = null; 
     onPost = BitmapFactory.decodeFile(google_user_gallery_pic); 
     if (onPost == null) 
     { 
      onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson); 
     } 

     else 
     { 
      onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
     } 
    } 
} 

else 
{ 
    onPost = null; 
    onPost2 = null; 
    onPost = BitmapFactory.decodeFile(google_user_gallery_pic); 
    if (onPost == null) 
    { 
     onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson); 
     //onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 

    else 
    { 
     onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false); 
    } 
}

由于所需的权限和别的，而不是这个代码片断，有什么不对比这个

好吧，让我试试这个兄弟 –

不，对不起兄弟... –

答

尝试其他使用picasso从URL加载图像位图。

compile 'com.squareup.picasso:picasso:2.5.2'

好的，什么这是目标吗？这是一堂课吗？ –

是的，你需要导入它..在添加gradle后 – rafsanahmad007

我认为逻辑有问题，因为它确实工作了一段时间，当我按照Saim的回答改变条件时... –

无法获取位图从谷歌个人资料图片url

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