锁定来电屏幕上的对话框

问题描述:

我希望可以点击对话框和来电屏幕。我已经尝试过不同的解决方案,但有些在某些情况下有效,而有些则不适用。我想创建一个像真正的来电者的应用程序,我从BroadcastReceiver调用了一个活动。当屏幕未锁定时,我的代码完美工作,因为传入的屏幕不是全屏。但是当屏幕全屏时,对话活动会在呼叫屏幕上出现几毫秒,然后进入呼叫屏幕。锁定来电屏幕上的对话框

这里是我的我的活动的代码,我从广播接收器

称为
public class IncomingCallActivity extends AppCompatActivity { 

private static final int MSG_ID_CHECK_TOP_ACTIVITY = 1; 

private String userName; 
private String TAG = IncomingCallActivity.class.getSimpleName(); 
private Window wind; 

private PowerManager powerManager; 
private PowerManager.WakeLock wakeLock; 

/*private ActivityManager mActivityManager; 
private boolean mDismissed = false;*/ 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 

    wind = this.getWindow(); 
    wind.requestFeature(Window.FEATURE_NO_TITLE); 
    wind.addFlags(WindowManager.LayoutParams.FLAG_DISMISS_KEYGUARD); 
    wind.addFlags(WindowManager.LayoutParams.FLAG_SHOW_WHEN_LOCKED); 
    wind.addFlags(WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON); 
    wind.addFlags(WindowManager.LayoutParams.FLAG_NOT_TOUCH_MODAL); 

    powerManager = (PowerManager)getSystemService(Context.POWER_SERVICE); 
    wakeLock = powerManager.newWakeLock(PowerManager.FULL_WAKE_LOCK, "My Lock"); 
    wakeLock.acquire(); 

    setContentView(R.layout.activity_incoming_call); 
    userName = getIntent().getStringExtra(IncomingCallReceiver.NAME_KEY); 

    final TextView textView = (TextView) findViewById(R.id.tvUsername); 
    textView.setText(userName); 

    final ImageView ivCancel = (ImageView) findViewById(R.id.ivCancel); 
    ivCancel.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      wakeLock.release(); 
      IncomingCallActivity.this.finish(); 
     } 
    }); 

} 

}

 //Add Permissions in Manifest file and don't forget to check overlay permission 
      <uses-permission android:name="android.permission.SYSTEM_ALERT_WINDOW"/> 
      <uses-permission android:name="android.permission.SYSTEM_OVERLAY_WINDOW"/> 

    //Create Class Level Variable or as per requirement 

       WindowManager.LayoutParams mWindowsParams; 
       WindowManager mWindowManager; 
       View mDialogView; 

    //initialize variable 
mWindowsParams =new WindowManager.LayoutParams(WindowManager.LayoutParams.MATCH_PARENT, 
            WindowManager.LayoutParams.WRAP_CONTENT, 
            WindowManager.LayoutParams.TYPE_SYSTEM_ERROR, 
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE, 
            PixelFormat.TRANSLUCENT); 
mWindowManager=(WindowManager)context.getSystemService(Context.WINDOW_SERVICE); 

//Add Window on your event 
mWindowManager.addView(mDialogView, mWindowsParams); 

//For Remove window 

if (mDialogView.getParent() != null) { 
     try { 
      mWindowManager.removeViewImmediate(mDialogView); 
      } catch (Exception e) { 

      } 
     } 
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我也试过,它将使来电屏幕无法点击,我想两个屏幕点击。 –

+0

添加相同的窗口参数,你将不会面临这个问题。我使用相同的代码显示在传入呼叫时弹出。并尝试添加对话框视图为LayoutInflater inflater =(LayoutInflater) myContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE); mDialogView = inflater.inflate(R.layout.small_pop_up_layout, null); –

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是的,它与给定的参数一起工作。一个巨大的(伟大)感谢Gautam。我挣扎了很久。 –