无法从输入流获取音频输入流
问题描述:
我想要获取代码中提供的URL上的声音文件并播放它(格式为mp3
)。我查看了一些与此问题相关的Stack Overflow问题,他们都说我得到了mp3plugin.jar
。无法从输入流获取音频输入流
在Eclipse中,我在Configure Build Path下将它添加为一个外部jar(因为它位于我的Downloads文件夹中,不知道它是否适合它)。我再次运行它,它仍然给我这个错误:
javax.sound.sampled.UnsupportedAudioFileException: could not get audio input stream from input stream
at javax.sound.sampled.AudioSystem.getAudioInputStream(Unknown Source)
at Starter.main(Starter.java:21)
下面是代码:
public class Starter {
public static void main(String[] args) {
AudioInputStream din = null;
try {
URL url = new URL("http://c5.rbxcdn.com/2e6d33a5b3b1d8f250c395816ff9f145");
HttpURLConnection httpcon = (HttpURLConnection) url.openConnection();
InputStream bufferedIn = new BufferedInputStream(httpcon.getInputStream());
AudioInputStream in = AudioSystem.getAudioInputStream(bufferedIn);
AudioFormat baseFormat = in.getFormat();
AudioFormat decodedFormat = new AudioFormat(
AudioFormat.Encoding.PCM_SIGNED,
baseFormat.getSampleRate(), 16, baseFormat.getChannels(),
baseFormat.getChannels() * 2, baseFormat.getSampleRate(),
false);
din = AudioSystem.getAudioInputStream(decodedFormat, in);
DataLine.Info info = new DataLine.Info(SourceDataLine.class, decodedFormat);
SourceDataLine line = (SourceDataLine) AudioSystem.getLine(info);
if(line != null) {
line.open(decodedFormat);
byte[] data = new byte[4096];
// Start
line.start();
int nBytesRead;
while ((nBytesRead = din.read(data, 0, data.length)) != -1) {
line.write(data, 0, nBytesRead);
}
// Stop
line.drain();
line.stop();
line.close();
din.close();
}
}
catch(Exception e) {
e.printStackTrace();
}
finally {
if(din != null) {
try { din.close(); } catch(IOException e) { }
}
}
}
}
答
你需要得到http://www.javazoom.net/mp3spi/docs/doc1.9.4/javazoom/spi/mpeg/sampled/file/MpegAudioFileReader.html
下载的罐子。我有我的类路径
.;C:\Vision\Audio\libs\vorbisspi1.0.3.jar;C:\Vision\Audio\libs\tritonus_share.jar;C:\Vision\Audio\libs\tritonus_remaining-0.3.6.jar;C:\Vision\Audio\libs\jorbis-0.0.15.jar;C:\Vision\Audio\libs\jogg-0.0.7.jar;C:\Vision\Audio\libs\jl1.0.jar;C:\Vision\Audio\libs\mp3spi1.9.4.jar;
,你可能只需要mp3spi1.9.4.jar - 其中一些是为其他格式,但我不知道,所以我要把它们全部。
然后让下面的程序
public AudioInputStream readMP3URL(String f) {
AudioInputStream audioInputStream=null;
AudioFormat targetFormat=null;
try {
AudioInputStream in=null;
MpegAudioFileReader mp=new MpegAudioFileReader();
in=mp.getAudioInputStream(new URL(f));
AudioFormat baseFormat=in.getFormat();
targetFormat=new AudioFormat(
AudioFormat.Encoding.PCM_SIGNED,
baseFormat.getSampleRate(),
16,
baseFormat.getChannels(),
baseFormat.getChannels() * 2,
baseFormat.getSampleRate(),
false);
audioInputStream=AudioSystem.getAudioInputStream(targetFormat, in);
}
catch(Exception ue) { System.out.println("\nUnsupported Audio"); }
return audioInputStream;
}
public void readURL() {
int i, j, k=0, l, basicU=1024;
AudioFormat targetFormat=null;
audioInputStream=readMP3URL("http://c5.rbxcdn.com/2e6d33a5b3b1d8f250c395816ff9f145");
if(audioInputStream==null) System.out.println("null audiostream");
targetFormat=audioInputStream.getFormat();
byte[] data=new byte[basicU];
DataLine.Info dinfo=new DataLine.Info(SourceDataLine.class, targetFormat);
SourceDataLine line=null;
try {
line=(SourceDataLine)AudioSystem.getLine(dinfo);
if(line!=null) {
line.open(targetFormat);
line.start();
while((k=audioInputStream.read(data, 0, data.length))!=-1) {
line.write(data, 0, k);
}
line.stop();
line.close();
}
}
catch(Exception ex) { ex.printStackTrace(); System.out.println("audio problem "+ex); }
}
你有没有检查你正在读什么?你可能会把一个html错误页面当作MP3。 – Marged
当我将该网址输入到我的Chrome浏览器时,我在网络标签中看到了2行。它可能需要一些更多的标题给你实际的流 – Gavriel
我怎么会得到这个媒体的一部分? (它说文件和媒体)。我听说jSoup可以帮助处理java中的一些html处理。 –