无法从输入流获取音频输入流

无法从输入流获取音频输入流

问题描述:

我想要获取代码中提供的URL上的声音文件并播放它(格式为mp3)。我查看了一些与此问题相关的Stack Overflow问题,他们都说我得到了mp3plugin.jar无法从输入流获取音频输入流

在Eclipse中,我在Configure Build Path下将它添加为一个外部jar(因为它位于我的Downloads文件夹中,不知道它是否适合它)。我再次运行它,它仍然给我这个错误:

javax.sound.sampled.UnsupportedAudioFileException: could not get audio input stream from input stream
at javax.sound.sampled.AudioSystem.getAudioInputStream(Unknown Source)
at Starter.main(Starter.java:21)

下面是代码:

public class Starter { 

    public static void main(String[] args) { 
     AudioInputStream din = null; 
     try { 
      URL url = new URL("http://c5.rbxcdn.com/2e6d33a5b3b1d8f250c395816ff9f145"); 
      HttpURLConnection httpcon = (HttpURLConnection) url.openConnection(); 
      InputStream bufferedIn = new BufferedInputStream(httpcon.getInputStream()); 
      AudioInputStream in = AudioSystem.getAudioInputStream(bufferedIn); 
      AudioFormat baseFormat = in.getFormat(); 
      AudioFormat decodedFormat = new AudioFormat(
        AudioFormat.Encoding.PCM_SIGNED, 
        baseFormat.getSampleRate(), 16, baseFormat.getChannels(), 
        baseFormat.getChannels() * 2, baseFormat.getSampleRate(), 
        false); 
      din = AudioSystem.getAudioInputStream(decodedFormat, in); 
      DataLine.Info info = new DataLine.Info(SourceDataLine.class, decodedFormat); 
      SourceDataLine line = (SourceDataLine) AudioSystem.getLine(info); 
      if(line != null) { 
       line.open(decodedFormat); 
       byte[] data = new byte[4096]; 
       // Start 
       line.start(); 

       int nBytesRead; 
       while ((nBytesRead = din.read(data, 0, data.length)) != -1) { 
        line.write(data, 0, nBytesRead); 
       } 
       // Stop 
       line.drain(); 
       line.stop(); 
       line.close(); 
       din.close(); 
      } 

     } 
     catch(Exception e) { 
      e.printStackTrace(); 
     } 
     finally { 
      if(din != null) { 
       try { din.close(); } catch(IOException e) { } 
      } 
     } 
    } 
} 
+1

你有没有检查你正在读什么?你可能会把一个html错误页面当作MP3。 – Marged

+0

当我将该网址输入到我的Chrome浏览器时,我在网络标签中看到了2行。它可能需要一些更多的标题给你实际的流 – Gavriel

+0

我怎么会得到这个媒体的一部分? (它说文件和媒体)。我听说jSoup可以帮助处理java中的一些html处理。 –

你需要得到http://www.javazoom.net/mp3spi/docs/doc1.9.4/javazoom/spi/mpeg/sampled/file/MpegAudioFileReader.html

下载的罐子。我有我的类路径

.;C:\Vision\Audio\libs\vorbisspi1.0.3.jar;C:\Vision\Audio\libs\tritonus_share.jar;C:\Vision\Audio\libs\tritonus_remaining-0.3.6.jar;C:\Vision\Audio\libs\jorbis-0.0.15.jar;C:\Vision\Audio\libs\jogg-0.0.7.jar;C:\Vision\Audio\libs\jl1.0.jar;C:\Vision\Audio\libs\mp3spi1.9.4.jar; 

,你可能只需要mp3spi1.9.4.jar - 其中一些是为其他格式,但我不知道,所以我要把它们全部。

然后让下面的程序

public AudioInputStream readMP3URL(String f) { 
AudioInputStream audioInputStream=null; 
AudioFormat targetFormat=null; 
try { 
    AudioInputStream in=null; 
    MpegAudioFileReader mp=new MpegAudioFileReader(); 
    in=mp.getAudioInputStream(new URL(f)); 
    AudioFormat baseFormat=in.getFormat(); 
targetFormat=new AudioFormat(
      AudioFormat.Encoding.PCM_SIGNED, 
      baseFormat.getSampleRate(), 
      16, 
      baseFormat.getChannels(), 
      baseFormat.getChannels() * 2, 
      baseFormat.getSampleRate(), 
      false); 
     audioInputStream=AudioSystem.getAudioInputStream(targetFormat, in); 
} 
catch(Exception ue) { System.out.println("\nUnsupported Audio"); } 
return audioInputStream; 
} 

public void readURL() { 
    int i, j, k=0, l, basicU=1024; 
    AudioFormat targetFormat=null; 
audioInputStream=readMP3URL("http://c5.rbxcdn.com/2e6d33a5b3b1d8f250c395816ff9f145"); 
    if(audioInputStream==null) System.out.println("null audiostream"); 
targetFormat=audioInputStream.getFormat(); 
byte[] data=new byte[basicU]; 
DataLine.Info dinfo=new DataLine.Info(SourceDataLine.class, targetFormat); 
SourceDataLine line=null; 
    try { 
    line=(SourceDataLine)AudioSystem.getLine(dinfo); 
    if(line!=null) { 
    line.open(targetFormat); 
    line.start(); 
     while((k=audioInputStream.read(data, 0, data.length))!=-1) { 
     line.write(data, 0, k); 
    } 
    line.stop(); 
    line.close(); 
    } 
} 
catch(Exception ex) { ex.printStackTrace(); System.out.println("audio problem "+ex); } 
}