JSON响应解析错误 - Javascript
我有以下来自API的JSON响应。JSON响应解析错误 - Javascript
{
"status": true,
"cakes": {
"7689": {
"id": 7689,
"flavor": "chocolate",
"cookDetails": {
"id": 101,
"firstName": "Name1",
"lastName": "LastName1"
}
},
"7690": {
"id": 7690,
"flavor": "vanilla",
"cookDetails": {
"id": 102,
"firstName": "Name2",
"lastName": "LastName2"
}
}
}
}
语言我使用解析此JSON:使用Javascript
框架:ReactNative
我的问题是:
1是JSON格式是否正确?
2.如果是的话,那我怎么分析它(注:我不知道ID的蛋糕的价值,直到我解析它)?
PS:新框架。十分感谢。
这里是有效的JSON(只是额外的逗号被拆除):
{
"status": true,
"cakes": {
"7689": {
"id": 7689,
"flavor": "chocolate",
"cookDetails": {
"id": 101,
"firstName": "Name1",
"lastName": "LastName1"
}
},
"7690": {
"id": 7690,
"flavor": "vanilla",
"cookDetails": {
"id": 102,
"firstName": "Name2",
"lastName": "LastName2"
}
}
}
}
您可以用普通电话JSON.parse解析它
downvote的原因是什么? – slesh
这不是我猜的完整答案。在回答问题之前请注意完整答案。如果您有意见,请随时留言。 – Vishnuvardhan
@slesh我已经更新了JSON响应。你能回答第二个问题吗(如何解析它)? – prasang7
尝试使用此,
{
"status": true,
"cakes": [{
"id": 7689,
"flavor": "chocolate",
"cookDetails": {
"id": 101,
"firstName": "Name1",
"lastName": "LastName1"
}
}, {
"id": 7690,
"flavor": "vanilla",
"cookDetails": {
"id": 102,
"firstName": "Name2",
"lastName": "LastName2"
}
}]
}
为ReactNative检查此:https://facebook.github.io/react-native/docs/network.html http://www.9lessons.info/2017/04/react-native-json-parsing-and-helper.html
请注意以下代码HTML JavaScript供您理解。
var obj = JSON.parse('{"status": true,"cakes": [{"id": 7689,"flavor": "chocolate","cookDetails": {"id": 101,"firstName": "Name1","lastName": "LastName1"}},{"id": 7690,"flavor": "vanilla","cookDetails": {"id": 102,"firstName": "Name2","lastName": "LastName2"}}]}');
<!DOCTYPE html>
<html>
<body>
<h2>Create Object from JSON String</h2>
<p id="demo"></p>
<script>
var obj = JSON.parse('{"status": true,"cakes": [{"id": 7689,"flavor": "chocolate","cookDetails": {"id": 101,"firstName": "Name1","lastName": "LastName1"}},{"id": 7690,"flavor": "vanilla","cookDetails": {"id": 102,"firstName": "Name2","lastName": "LastName2"}}]}');
document.getElementById("demo").innerHTML = obj.cakes[0].id +", "+ obj.cakes[0].flavor+", "+obj.cakes[0].cookDetails.id+", "+obj.cakes[0].cookDetails.firstName+", "+obj.cakes[0].cookDetails.lastName;
</script>
</body>
</html>
您的JSON是不正确的,检查这里https://jsonlint.com/,你有3个无用的逗号。 2在LastName末尾,最后 – AshBringer
JSON不正确。冒号是不允许的{ –
JOSN不正确 –