用线连接图像

问题描述:

我试图用线测验进行两对匹配。我在左边有几张图片,右边有几张图片,当你点击一对图片时,我需要将它与线条连接起来。它应该适用于任何组合,所以如果我点击左侧的图像1和右侧的图像3,它们应该用线连接。然后,如果我再次点击右侧的图像1和左侧的图像2,则应删除上一行,并且需要创建这两个图像之间的新图像。 HTML片段:用线连接图像

function lineDistance(x, y, x0, y0){ 
 
    return Math.sqrt((x -= x0) * x + (y -= y0) * y); 
 
}; 
 

 
function drawLine(a, b, line) { 
 
    var pointA = $(a).offset(); 
 
    var pointB = $(b).offset(); 
 
    var pointAcenterX = $(a).width()/2; 
 
    var pointAcenterY = $(a).height()/2; 
 
    var pointBcenterX = $(b).width()/2; 
 
    var pointBcenterY = $(b).height()/2; 
 
    var angle = Math.atan2(pointB.top - pointA.top, pointB.left - pointA.left) * 180/Math.PI; 
 
    var distance = lineDistance(pointA.left, pointA.top, pointB.left, pointB.top); 
 

 
// Set Angle 
 
    $(line).css('transform', 'rotate(' + angle + 'deg)'); 
 

 

 
    // Set Width 
 
    $(line).css('width', distance + 'px'); 
 
        
 
    // Set Position 
 
    $(line).css('position', 'absolute'); 
 
    if(pointB.left < pointA.left) { 
 
    $(line).offset({top: pointA.top + pointAcenterY, left: pointB.left + pointBcenterX}); 
 
    } else { 
 
    $(line).offset({top: pointA.top + pointAcenterY, left: pointA.left + pointAcenterX}); 
 
    } 
 
} 
 
new drawLine('.a', '.b', '.line');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<div class="question"> 
 
    <div id="old" class="left_side one_half svg left"> 
 
    <a href="#" data-number="1"><img class="a" src="assets/svg/Kerze.svg"></a> 
 
    <a href="#" data-number="2"><img src="assets/svg/Telefon.svg"></a> 
 
    <a href="#" data-number="3"><img src="assets/svg/Schreibmaschine.svg"></a> 
 
    <a href="#" data-number="4"><img src="assets/svg/TV_old.svg"></a> 
 
    <a href="#" data-number="5"><img src="assets/svg/Zeitstopper.svg"></a> 
 
    <a href="#" data-number="6"><img src="assets/svg/Besen.svg"></a> 
 
    <a href="#" data-number="7"><img src="assets/svg/Waschen.svg"></a> 
 
    </div> 
 
    <div class="left_side one_half svg right"> 
 
    <a href="#" data-letter="NS"><img src="assets/svg/Iwatch.svg"></a> 
 
    <a href="#" data-letter="RT"><img src="assets/svg/Laptop.svg"></a> 
 
    <a href="#" data-letter="TE"><img src="assets/svg/Staubsauger.svg"></a> 
 
    <a href="#" data-letter="IN"><img src="assets/svg/Waschmaschine.svg"></a> 
 
    <a href="#" data-letter="EI"><img src="assets/svg/TV_new.svg"></a> 
 
    <a href="#" data-letter="AL"><img src="assets/svg/Gluehbirne.svg"></a> 
 
    <a href="#" data-letter="BE"><img class="b" src="assets/svg/Iphone.svg"></a> 
 
    <div class="line"></div> 
 
    </div> 
 
</div>

我管理,使两个图像(从类B类)之间的线,并且它总是计算为恰好在直角,但是我不会使它看起来像我上面所描述的那样工作。有任何想法吗?谢谢。

var setLeft = false, setRight = false; 
$('.leftSide img').click(function(){ 
    $('.leftSide img').removeClass('a'); 
    $(this).addClass('a'); 
    setLeft = true; 
    new drawLine('.a', '.b', '.line'); 
}); 
$('.rightSide img').click(function(){ 
    $('.rightSide img').removeClass('b'); 
    $(this).addClass('b'); 
    setRight = true; 
    new drawLine('.a', '.b', '.line'); 
}); 

你可以用一个标志变量,当单击右侧的图像上,设定正确的国旗变量是真实的和做同样与其他。

然后你的函数里面drawLine只是检查,如果这两个标志是真,那么绘制ab之间的界限,并设置两个标志变量false

function lineDistance(x, y, x0, y0){ 
 
    return Math.sqrt((x -= x0) * x + (y -= y0) * y); 
 
}; 
 

 
function drawLine(a, b, line) { 
 

 
\t if(setLeft && setRight){ 
 
    \t setLeft = false; 
 
    setRight = false; 
 
    var pointA = $(a).offset(); 
 
    var pointB = $(b).offset(); 
 
    console.log(pointA); 
 
    console.log(pointB); 
 
    var pointAcenterX = $(a).width()/2; 
 
    var pointAcenterY = $(a).height()/2; 
 
    var pointBcenterX = $(b).width()/2; 
 
    var pointBcenterY = $(b).height()/2; 
 
    var angle = Math.atan2(pointB.top - pointA.top, pointB.left - pointA.left) * 180/Math.PI; 
 
    var distance = lineDistance(pointA.left, pointA.top, pointB.left, pointB.top); 
 

 
    // Set Angle 
 
    $(line).css('transform', 'rotate(' + angle + 'deg)'); 
 

 

 
    // Set Width 
 
    $(line).css('width', distance + 'px'); 
 

 
    // Set Position 
 
    $(line).css('position', 'absolute'); 
 
    if(pointB.left < pointA.left) { 
 
     $(line).offset({top: pointA.top + pointAcenterY, left: pointB.left + pointBcenterX}); 
 
    } else { 
 
     $(line).offset({top: pointA.top + pointAcenterY, left: pointA.left + pointAcenterX}); 
 
    } 
 
    } 
 
} 
 
//new drawLine('.a', '.b', '.line'); 
 
var setLeft = false, setRight = false; 
 
$('.leftSide img').click(function(){ 
 
\t $('.leftSide img').removeClass('a'); 
 
\t $(this).addClass('a'); 
 
    setLeft = true; 
 
    new drawLine('.a', '.b', '.line'); 
 
}); 
 
$('.rightSide img').click(function(){ 
 
\t $('.rightSide img').removeClass('b'); 
 
\t $(this).addClass('b'); 
 
    setRight = true; 
 
    new drawLine('.a', '.b', '.line'); 
 
});
.left{ 
 
    float:left; 
 
} 
 
.right{ 
 
    float:right; 
 
} 
 
.one_half{ 
 
    width:40%; 
 
} 
 
img{ 
 
    max-width:100%; 
 
} 
 
.line{ 
 
    background: red; 
 
    height:1px; 
 
} 
 
.question{ 
 
    position: relative; 
 
    overflow: hidden; 
 
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<div class="question"> 
 
    <div id="old" class="left_side one_half svg left leftSide"> 
 
    <a href="#" data-number="1"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="2"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="3"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="4"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="5"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="6"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-number="7"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    </div> 
 
    <div class="left_side one_half svg right rightSide"> 
 
    <a href="#" data-letter="NS"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="RT"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="TE"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="IN"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="EI"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="AL"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <a href="#" data-letter="BE"><img src="https://www.w3schools.com/css/trolltunga.jpg"></a> 
 
    <div class="line"></div> 
 
    </div> 
 
</div>

+0

感谢answer.That是一个良好的开端,只是有一个问题,即行仅显示了一对,当我点击另一对OG图像,前行消失了,而且,当你点击左下方图像右侧的图像时,它的效果很好,当我尝试将图像放在左上方的图像上方时,该线条连接不好。 –