画布旋转时的getbounds

Question

我需要获取画布内部图像的边界以检测是否已被触摸，但如果旋转画布，getbounds（）会保持相同的值，那么我如何获取画布旋转后的正确值？

//CODE ON VIEW CLASS: 

    canvas.save(); 
    canvas.rotate(rotation, Xpos, Ypos); 

    secHandImg.setBounds(left,top,right,bottom);  
    secHandImg.setAntiAlias(true); 
    secHandImg.draw(canvas); 

    circleHandImg.setBounds(left,top,right,bottom); 
    circleHandImg.setAntiAlias(true); 
    circleHandImg.draw(canvas); 

    canvas.restore(); 


//CODE ON FRAGMENT CLASS: 

     public boolean onTouch(View view, MotionEvent event) { 

       Rect imageBounds = MyClass.secHandImg.getBounds();   

       int action = event.getAction(); 

       final int x = (int)event.getX(); 
       final int y = (int)event.getY(); 


        if(action == MotionEvent.ACTION_DOWN) { 

    if(x >= imageBounds.left && x < (imageBounds.left + imageBounds.width()) 
    && y >= imageBounds.top && y < (imageBounds.top + imageBounds.height())){ 

//THIS DON´T WORK IF CANVAS ROTATES 
       imageBoundsTouch = true; 


       } 

     } 

这里的图像更好地说明我的问题：

http://s11.postimg.org/z7j0xgwmb/Imagen_2.png

Answer 1

可以使用三角得到旋转矩形的界限：

function BBoxDimensions(width,height,radianAngle){ 
    var c = Math.abs(Math.cos(radianAngle)); 
    var s = Math.abs(Math.sin(radianAngle)); 
    return({ width: height * s + width * c, height: height * c + width * s }); 
} 

而且你可以使用三克至获得XY旋转边框：

// where cx/cy is the center of rotation of the target 
// and startingX/startingY is the starting xy of the unrotated target 

var x1 = startingX - cx; 
var y1 = startingY - cy; 
newX =cx+ x1*Math.cos(angle) - y1*Math.sin(angle); 
newY =cy+ y1*Math.cos(angle) + x1*Math.sin(angle); 

Answer 2

重新计算你的边界值onOrientationChanged（）