Android:使用php上传服务器上的图像

问题描述:

始终在服务器上传0KB图像test.jpg!Android:使用php上传服务器上的图像

这里是图片:

http://s11.postimage.org/xz6gbi1rl/Capture_Problem_Android.jpg

所以你可以看到我收到的服务器上的内容。

我希望得到任何帮助或建议,我希望我会解决这个问题..

的Android代码:

 public class Main extends Activity { 

InputStream inputStream; 
    @Override 
    public void onCreate(Bundle icicle) { 
    super.onCreate(icicle); 
    setContentView(R.layout.main); 

    Bitmap bitmap = BitmapFactory.decodeResource(getResources(),R.drawable.ic_launcher); 
    ByteArrayOutputStream stream = new ByteArrayOutputStream(); 
    bitmap.compress(Bitmap.CompressFormat.PNG, 90, stream); //compress to which format you want. 
    byte [] byte_arr = stream.toByteArray(); 
    String image_str = Base64.encodeBytes(byte_arr); 
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); 

    nameValuePairs.add(new BasicNameValuePair("image",image_str)); 

    try{ 
     HttpClient httpclient = new DefaultHttpClient(); 
     HttpPost httppost = new HttpPost("http://server/uploader2.php"); 
     httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
     HttpResponse response = httpclient.execute(httppost); 
     String the_string_response = convertResponseToString(response); 
     Toast.makeText(this, "Response " + the_string_response, Toast.LENGTH_LONG).show(); 
    }catch(Exception e){ 
      Toast.makeText(this, "ERROR " + e.getMessage(), Toast.LENGTH_LONG).show(); 
      System.out.println("Error in http connection "+e.toString()); 
    } 
} 

public String convertResponseToString(HttpResponse response) throws IllegalStateException, IOException{ 

    String res = ""; 
    StringBuffer buffer = new StringBuffer(); 
    inputStream = response.getEntity().getContent(); 
    int contentLength = (int) response.getEntity().getContentLength(); //getting content length….. 
    Toast.makeText(this, "contentLength : " + contentLength, Toast.LENGTH_LONG).show(); 
    if (contentLength < 0){ 
    } 
    else{ 
      byte[] data = new byte[512]; 
      int len = 0; 
      try 
      { 
       while (-1 != (len = inputStream.read(data))) 
       { 
        buffer.append(new String(data, 0, len)); //converting to string and appending to stringbuffer….. 
       } 
      } 
      catch (IOException e) 
      { 
       e.printStackTrace(); 
      } 
      try 
      { 
       inputStream.close(); // closing the stream….. 
      } 
      catch (IOException e) 
      { 
       e.printStackTrace(); 
      } 
      res = buffer.toString();  // converting stringbuffer to string….. 

      Toast.makeText(this, "Result : " + res, Toast.LENGTH_LONG).show(); 
      //System.out.println("Response => " + EntityUtils.toString(response.getEntity())); 
    } 
    return res; 


}} 

和PHP代码...(uploader2.php)

<?php 
$base=$_REQUEST['image']; 
$binary=base64_decode($base); 
header('Content-Type: image/jpg; charset=utf-8'); 
$file = fopen('test.jpg', 'wb'); 
fwrite($file, $binary); 
fclose($file); 
echo 'Image upload complete!!, Please check your php file directory……'; 
echo "<img src=test.jpg>"; 
?> 

有什么问题?

doFileUpload功能:

private void doFileUpload(){ 
    HttpURLConnection conn = null; 
    DataOutputStream dos = null; 
    DataInputStream inStream = null; 
    String exsistingFileName = "/sdcard/six.3gp"; 
    // Is this the place are you doing something wrong. 
    String lineEnd = "\r\n"; 
    String twoHyphens = "--"; 
    String boundary = "*****"; 
    int bytesRead, bytesAvailable, bufferSize; 
    byte[] buffer; 
    int maxBufferSize = 1*1024*1024; 
    String urlString = "http://192.168.1.5/upload.php"; 
    try 
    { 
     Log.e("MediaPlayer","Inside second Method"); 
     FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName)); 
     URL url = new URL(urlString); 
     conn = (HttpURLConnection) url.openConnection(); 
     conn.setDoInput(true); 
     // Allow Outputs 
     conn.setDoOutput(true); 
     // Don't use a cached copy. 
     conn.setUseCaches(false); 
     // Use a post method. 
     conn.setRequestMethod("POST"); 
     conn.setRequestProperty("Connection", "Keep-Alive"); 
     conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); 
     dos = new DataOutputStream(conn.getOutputStream()); 
     dos.writeBytes(twoHyphens + boundary + lineEnd); 
     dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd); 
     dos.writeBytes(lineEnd); 
     Log.e("MediaPlayer","Headers are written"); 
     bytesAvailable = fileInputStream.available(); 
     bufferSize = Math.min(bytesAvailable, maxBufferSize); 
     buffer = new byte[bufferSize]; 
     bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
     while (bytesRead > 0) 
     { 
      dos.write(buffer, 0, bufferSize); 
      bytesAvailable = fileInputStream.available(); 
      bufferSize = Math.min(bytesAvailable, maxBufferSize); 
      bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
     } 
     dos.writeBytes(lineEnd); 
     dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 
     BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream())); 
     String inputLine; 
     while ((inputLine = in.readLine()) != null) 
      tv.append(inputLine); 
     // close streams 
     Log.e("MediaPlayer","File is written"); 
     fileInputStream.close(); 
     dos.flush(); 
     dos.close(); 
    } 
    catch (MalformedURLException ex) 
    { 
     Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); 
    } 
    catch (IOException ioe) 
    { 
     Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); 
    } 

    //------------------ read the SERVER RESPONSE 
    try { 
     inStream = new DataInputStream (conn.getInputStream()); 
     String str;    
     while ((str = inStream.readLine()) != null) 
     { 
      Log.e("MediaPlayer","Server Response"+str); 
     } 
     /*while((str = inStream.readLine()) !=null){ 

     }*/ 
     inStream.close(); 
    } 
    catch (IOException ioex){ 
     Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); 
    } 
} 

upload.php的

<?php 

move_uploaded_file($_FILES['uploadedfile']['tmp_name'], "./upload/".$_FILES["uploadedfile"]["name"]); 

mysql_connect("localhost","root",""); 
     mysql_select_db("chat"); 


if(isset($_REQUEST['msg'])) 
{ 
    $a = $_REQUEST['msg']; 
    $sql = "INSERT INTO upload(image)VALUES('$a')"; 
    mysql_query($sql); 
    } 
?> 
+0

作品完美,谢谢! –

+2

我假设'tv.append(inputline);'是一个文本视图,但你使用它的目的是什么? – jcaruso

+0

你会想要使用AsyncTask关闭课程。 – TastyLemons