如何通过在类中创建的方法在窗体上创建按钮?
问题描述:
我想根据用户输入的行数和列数创建一个按钮的网格,并且我的创建网格的方法不起作用。当我称之为网格不会被创建。如何通过在类中创建的方法在窗体上创建按钮?
该方法在我的TileClass中,我试图在我的GameBoard窗体中调用它。我觉得我不适当地使用课堂。我不认为我正确调用方法,因为我认为这应该工作。
This is what the form looks like
class TileClass : Button
{
public const int LEFT = 20;
public const int WIDTH = 50;
public const int HEIGHT = 50;
public const int TOP = 50;
public const int VGAP = 30;
public int x;
public int y;
public int column;
public int row;
private int incomingRow;
private int incomingColumn;
public int IncomingRow { get => incomingRow; set => incomingRow = value; }
public int IncomingColumn { get => incomingColumn; set => incomingColumn = value; }
public TileClass()
{
}
public void CreateGrid()
{
x = LEFT;
y = TOP;
column = IncomingColumn;
row = IncomingRow;
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
Button b = new Button();
b.Left = x;
b.Top = y;
b.Width = WIDTH;
b.Height = HEIGHT;
b.Text = j.ToString();
x += VGAP + HEIGHT;
this.Controls.Add(b);
}
}
}
}
游戏键盘形式
public partial class GameBoard : Form
{
TileClass tileClass = new TileClass();
public GameBoard()
{
InitializeComponent();
}
private void txtEnter_Click(object sender, EventArgs e)
{
tileClass.IncomingColumn = int.Parse(txtColumn.Text);
tileClass.IncomingRow = int.Parse(txtRow.Text);
tileClass.CreateGrid();
}
答
还有很多事情要做,以做到这一点:
class TileClass : Panel
{
...
public int IncomingRow {get; set;}
public int IncomingColumn { get; set; }
...
}
,并删除:
private int incomingRow;
private int incomingColumn;
理想的方法是在添加按钮之前使用ResumeLayout,并通过调用Invalidate来重绘Gameboard表单。 What does invalidate method do? 注:尽量山坳= 100,排= 100与不ResumeLayout &的Invalidate
public partial class GameBoard : Form
{
public GameBoard()
{
InitializeComponent();
tileClass.Dock = DockStyle.Fill;
this.Controls.Add(tileClass);
}
TileClass tileClass = new TileClass();
private void txtEnter_Click(object sender, EventArgs e)
{
tileClass.IncomingColumn = int.Parse(txtColumn.Text);
tileClass.IncomingRow = int.Parse(txtRow.Text);
this.ResumeLayout(); //Important
tileClass.CreateGrid();
this.Invalidate(); // Important
}
}
和喜欢,它需要比这更多,你可以设置更多的属性:
//tileClass.Location = new Point(10, 10); // not sure
tileClass.Dock = DockStyle.Fill;
//tileClass.Size = new Size(200, 200); // not sure
和替代Ĵ < 5你应该使用列和行:
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
Button b = new Button();
b.Left = x;
b.Top = y;
b.Width = WIDTH;
b.Height = HEIGHT;
b.Text = string.Format("({0},{1})" , i, j);
x += VGAP + HEIGHT;
this.Controls.Add(b);
}
x = LEFT; // not sure, plz calculate!
y += Top * (i+1); // not sure, plz calculate!
}
这是什么意思'不工作'?你有一个从类继承的新类,它的方法创建了更多的按钮。你不应该从按钮继承这个类。它应该从控制面板或组框中继承。 –
哇,你去解决所有这些麻烦来解析值,并存储'IncomingCollumn'和'IncomingRow',然后将它们传递给字段,然后将其传递给局部变量......然后你不会对它们做任何事情。你不觉得你的for循环应该看行列数吗? –