Android将意图从onclick按钮创建编程 - 未找到活动例外

Question

我必须意图通过点击一个按钮，其中整个布局是以编程方式创建的。 我检查了'Android content activity not found exception'的所有答案，并尝试了所有答案。但问题仍然存在。我使用了try catch块，但问题仍然存在。

protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 

     db = new DBOperation(this); 
     document = getIntent().getStringExtra("document_id"); 
     getAlldataList=db.getPartiesReport(db); 
     LinearLayout rootView = new LinearLayout(this); 
     LinearLayout rootView1 = new LinearLayout(this); 
//  RelativeLayout rootView2 = new RelativeLayout(this); 

     Button update1 = new Button(this); 
     update1.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT)); 
     update1.setGravity(Gravity.CENTER); 
     update1.setText("UPDATE"); 

     update1.setBackgroundColor(Color.parseColor("#ffa500")); 
     update1.setTextColor(Color.WHITE); 
     LinearLayout.LayoutParams params = (LinearLayout.LayoutParams) update1.getLayoutParams(); 
     params.setMargins(20, 20, 20, 10); 
     update1.setLayoutParams(params); 
     update1.setOnClickListener(new OnClickListener() { 
      @Override 
      public void onClick(View v) { 
       for (int i = 0; i < poslist.size(); i++) { 
// 

//     SQLiteDatabase base3 = db.getWritableDatabase(); 
//     base3.delete(UPDATEPARTIES1, null, null); 
//     System.out.println("Parties DB Deleted"); 
        SQLiteDatabase db7 = db.getWritableDatabase(); 
        ContentValues values5= new ContentValues(); 
        values5.put(DBManager.TableInfo.KEYID, ID1); 
        values5.put(DBManager.TableInfo.DOCUMENT, document); 
        values5.put(DBManager.TableInfo.ATTENDANCE,attendancelist.get(i)); 
        values5.put(DBManager.TableInfo.EMAILNEW, emaillist.get(i)); 
        values5.put(DBManager.TableInfo.PARTYTYPE,partytypelist.get(i)); 
        values5.put(DBManager.TableInfo.BIOMETRIC,biometriclist.get(i)); 
        values5.put(DBManager.TableInfo.KEY_LOGIN_USER,username2); 
        String condition5 = DBManager.TableInfo.DOCUMENT + " =?"; 
        Cursor cursor5 = db7.query(DBManager.TableInfo.UPDATEPARTIES1, null, condition5, new String[]{DBManager.TableInfo.ATTENDANCE}, null, null, null); 
        long status5 = db7.insert(DBManager.TableInfo.UPDATEPARTIES1, null, values5); 
        System.out.println("Parties insert : " + status5); 
        cursor5.close(); 
        db7.close(); 
       } 

       itemlist.clear(); 
       poslist.clear(); 
       IDlist.clear(); 
       attendancelist.clear(); 
       partytypelist.clear(); 
       emaillist.clear(); 
       biometriclist.clear(); 
       System.out.println("Poslist:" + poslist.size()); 
       System.out.println("itemlist:" + itemlist.size()); 
       System.out.println("IDlist:" + IDlist.size()); 
       Intent i1=new Intent(anulom.executioner5.com3.anulom.newstatusinfo.this,SendPartyReport.class); 
       startActivity(i1); 
       finish(); 
      } 
     }); 

What I need is to do put a intent to a service SENDPARTYREPORT from the onclick listener of button UPDATE 1.

Answer 1

你必须调用

startService(i1); 

代替

startActivity(i1); 

出现异常是因为您尝试启动活动，而不是服务。如果我不确定您是否正确指出SendPartyReport是服务，那么您将不得不使用startService方法。

问候