在屏幕的最左侧显示ListPopupWindow

问题描述：

通过以下代码，我可以在屏幕的最左侧显示ListPopupWindow。在屏幕的最左侧显示ListPopupWindow

@Override 
public View onCreateActionView() { 
    LayoutInflater layoutInflater = LayoutInflater.from(mContext); 

    final View actionItem = layoutInflater.inflate(R.layout.list_table_view_action_provider, null); 

    final ImageButton button = (ImageButton) actionItem.findViewById(R.id.button); 
    button.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      mListPopupWindow = new ListPopupWindow(mContext); 
      mListPopupWindow.setAnchorView(actionItem); 
      mListPopupWindow.setAdapter(mAdapter); 
      mListPopupWindow.setModal(true); 
      mListPopupWindow.setContentWidth(150); 

      // Display mListPopupWindow on most left of the screen 
      mListPopupWindow.setHorizontalOffset(-1000); 


      mListPopupWindow.setOnItemClickListener(ListTableViewActionProvider.this); 

      mListPopupWindow.show(); 
      mListPopupWindow.setOnDismissListener(ListTableViewActionProvider.this); 
     } 
    }); 

    return actionItem; 
}

“mListPopupWindow.setHorizontalOffset（-1000）;”太糟糕了。是否有其他解决方案？

尝试具有最外面的布局/活性作为锚，并用0 偏移或也可以使用一个PopupWindow并给出x和y为的ViewGroup 0 – Varun 2012-03-28 11:48:20

我可以锚定在主页图标吗？ – dadachi 2012-03-28 12:23:57

您可以锚定到主图标，使用'findViewById（android.R.id.home）'来获取视图。弹出窗口不会与屏幕左边缘齐平;主页图标左侧有一些边距（为“向上”可供选择的箭头腾出空间）。 – Karakuri 2013-01-07 16:54:00

答

这里是ListPopupWindow例如，

 View menuItemView = getActivity().findViewById(R.id.menu_filter); 
     ListPopupWindow popup  = new ListPopupWindow(getActivity()); 

     popup.setHorizontalOffset(-200); 
     popup.setVerticalOffset(-100); 

     popup.setAnchorView(menuItemView); 
     popup.setWidth(400); 
     popup.setModal(true); 
     popup.setHeight(ListPopupWindow.WRAP_CONTENT); 

     ListAdapter adapter = new MyAdapter(getActivity()); 
     popup.setAdapter(adapter); 

     popup.show();

在屏幕的最左侧显示ListPopupWindow

相关推荐