以编程方式从底部裁剪图像
问题描述:
答
夫特
3溶液:
func cropBottomImage(image: UIImage) -> UIImage {
let height = CGFloat(image.size.height/3)
let rect = CGRect(x: 0, y: image.size.height - height, width: image.size.width, height: height)
return cropImage(image: image, toRect: rect)
}
用于与矩形裁剪Helper方法:
func cropImage(image:UIImage, toRect rect:CGRect) -> UIImage{
let imageRef:CGImage = image.cgImage!.cropping(to: rect)!
let croppedImage:UIImage = UIImage(cgImage:imageRef)
return croppedImage
}
答
方法:
func croppIngimage(ImageCrop:UIImage, toRect rect:CGRect) -> UIImage{
var imageRef:CGImageRef = CGImageCreateWithImageInRect(imageToCrop.CGImage, rect)
var croppedimage:UIImage = UIImage(CGImage:imageRef)
return croppedimage
}
呼叫:
var ImageCrop:UIImage = UIImage(named:"image.png")
答
这几乎是Alexburtnik的回答
只是提一提,UIImage.size是逻辑大小(以 “点”)
然而,CGImage.cropping()使用的实际尺寸(在“像素”中)
因此,如果您使用带有@ 2x或@ 3x修改器的图像,则会发现 裁剪实际上只是期望的一半或三分之一。
所以当你裁剪,你可以考虑先RECT通过图像的“尺度”属性相乘,如下所示:
func cropImage(image:UIImage, toRect rect:CGRect) -> UIImage? {
var rect = rect
rect.size.width = rect.width * image.scale
rect.size.height = rect.height * image.scale
guard let imageRef = image.cgImage?.cropping(to: rect) else {
return nil
}
let croppedImage = UIImage(cgImage:imageRef)
return croppedImage
}
答
作为扩展的UIImage:
import UIKit
extension UIImage {
func crop(to rect: CGRect) -> UIImage? {
// Modify the rect based on the scale of the image
var rect = rect
rect.size.width = rect.size.width * self.scale
rect.size.height = rect.size.height * self.scale
// Crop the image
guard let imageRef = self.cgImage?.cropping(to: rect) else {
return nil
}
return UIImage(cgImage: imageRef)
}
}
用法:
let myImage = UIImage(named:"myImage.png")
let croppedRect = CGRect(x: 0, y: 0, width: newWidth, height: newHeight)
let croppedImage = myImage.crop(to: croppedRect)
假设我有一个图像大小2448×3264我想那部分,即红色的一个。什么是toRect参数? – BornShell
看到这个:http://stackoverflow.com/questions/37946990/cgrectmake-cgpointmake-cgsizemake-cgrectzero-cgpointzero-is-unavailable-in –