弹出窗口不滚动时关闭
问题描述:
我有一个文本框,当它有焦点时弹出窗口出现在它下面。但是当弹出窗口打开并且我滚动时,它似乎停留在它打开的同一个位置。我需要帮助确定如何在滚动时在文本框下方显示弹出窗口。我将如何在xaml中做到这一点?弹出窗口不滚动时关闭
谢谢!
主窗口视图:
<Grid x:Name="LayoutRoot">
<ScrollViewer>
<local:ControlView/>
</ScrollViewer>
</Grid>
资源词典:
<Style TargetType="{x:Type Popup}">
<Style.Triggers>
<DataTrigger Binding="{Binding ElementName=txtTest, Path=IsKeyboardFocused}" Value="True">
<Setter Property="IsOpen" Value="True" />
</DataTrigger>
<DataTrigger Binding="{Binding ElementName=txtTest, Path=IsKeyboardFocused }" Value="False">
<Setter Property="IsOpen" Value="False" />
</DataTrigger>
</Style.Triggers>
</Style>
<Style x:Key="BorderStyle" TargetType="{x:Type Border}">
<Setter Property="Background" Value="LemonChiffon"/>
<Setter Property="Padding" Value="5"/>
</Style>
用户控件查看:
<Grid x:Name="LayoutRoot">
<StackPanel Grid.Row="1" Grid.Column="4" Orientation="Vertical">
<Button Content="Button" Width="100" Height="100"/>
<Button Content="Button" Width="100" Height="100"/>
<TextBox x:Name="txtTest" HorizontalAlignment="Stretch"/>
<Popup Name="TestPopup" StaysOpen="True"
PlacementTarget="{Binding ElementName=txtTest}"
AllowsTransparency="True" Placement="{Binding ElementName=txtTest}">
<Border Style="{DynamicResource BorderStyle}">
<GroupBox Header="Test Popup">
<ScrollViewer Margin="0,2,0,0" VerticalScrollBarVisibility="Hidden">
<!--BINDING-->
<Label Content="Hello World!"/>
</ScrollViewer>
</GroupBox>
</Border>
</Popup>
<ContentPresenter Content="{Binding testBinding}"
VerticalAlignment="Stretch" HorizontalAlignment="Stretch">
</ContentPresenter>
</StackPanel>
</Grid>
答
试试这个:
<Style TargetType="{x:Type Popup}">
<Setter
Property="IsOpen"
Value="{Binding IsKeyboardFocusedWithin, ElementName=txtTest, Mode=OneWay}"/>
</Style>
你能发表一些代码吗?像什么容器是文本框? – 2012-03-09 19:45:08
您已阅读过http://stackoverflow.com/questions/2309883/wpf-detect-scrolling-parent-control? – 2012-03-11 02:08:20
您应该在打开时提供弹出式对焦。这种方式你不应该能够滚动,除非弹出关闭。我发现的最好方法是看看组合框控件模板如何在msdn上工作:http://msdn.microsoft.com/en-us/library/ms752094(v=vs.90).aspx – Silvermind 2012-03-11 17:29:12