如何使用PHP获取用户的'contactid'使用谷歌API

Question

我想通过谷歌API 3.0获取所有用户详细信息的用户联系人。 我能够得到与用户的细节JSON响应。

$url = 'https://www.google.com/m8/feeds/contacts/default/full?max-results='.$max_results.'&alt=json&v=3.0&oauth_token='.$accesstoken; 

结果是

[entry] => Array 
      (
       [0] => Array 
        (
         [id] => Array 
          (
           [$t] => http://www.google.com/m8/feeds/contacts/sfdhitdf1%40gmail.com/base/1 
          ) 

         [gd$etag] => "RXc7fTVSLit7I2A9XRZaEkoLRAw." 
         [updated] => Array 
          (
           [$t] => 2014-08-29T00:16:24.905Z 
          ) 

         [app$edited] => Array 
          (
           [xmlns$app] => http://www.w3.org/2007/app 
           [$t] => 2014-08-29T00:16:24.905Z 
          ) 

         [category] => Array 
          (
           [0] => Array 
            (
             [scheme] => http://schemas.google.com/g/2005#kind 
             [term] => http://schemas.google.com/contact/2008#contact 
            ) 

          ) 

         [title] => Array 
          (
           [$t] => abc 
          ) 

         [link] => Array 
          (
           [0] => Array 
            (
             [rel] => http://schemas.google.com/contacts/2008/rel#photo 
             [type] => image 
             [href] => https://www.google.com/m8/feeds/photos/media/sachdfwdfd%40gmail.com/1?v=3.0 
             [gd$etag] => "VWVIH3oyWit7I2B0UBRURzwNBWM8ODs8cSk." 
            ) 

           [1] => Array 
            (
             [rel] => self 
             [type] => application/atom+xml 
             [href] => https://www.google.com/m8/feeds/contacts/sachitdff%40gmail.com/full/1?v=3.0 
            ) 

           [2] => Array 
            (
             [rel] => edit 
             [type] => application/atom+xml 
             [href] => https://www.google.com/m8/feeds/contacts/sachidtfd%40gmail.com/full/1?v=3.0 
            ) 

          ) 

         [gd$name] => Array 
          (
           [gd$fullName] => Array 
            (
             [$t] => abc xyz 
            ) 

           [gd$givenName] => Array 
            (
             [$t] => abc 
            ) 

           [gd$familyName] => Array 
            (
             [$t] => xyz 
            ) 

          ) 

         [gd$email] => Array 
          (
           [0] => Array 
            (
             [address] => [email protected] 
             [primary] => true 
             [rel] => http://schemas.google.com/g/2005#other 
            ) 

          ) 

         [gContact$website] => Array 
          (
           [0] => Array 
            (
             [href] => http://www.google.com/profiles/104048264070958665151 
             [rel] => profile 
            ) 

          ) 

         [gContact$groupMembershipInfo] => Array 
          (
           [0] => Array 
            (
             [deleted] => false 
             [href] => http://www.google.com/m8/feeds/groups/sachitaware 

          ) 

        ) 

但在这里我不明白的接触式图像的user.The documentation说我需要一个接触式ID用于获取照片，但我不明白上述回复中的联系人ID。如何获取用户的联系人ID以及他的联系人照片？

我已经授权使用oauth 2.0的应用程序，除了图像以外，我获得了大部分联系人的详细信息。

编辑：我试图this方式从文档和它的作品，但它返回的二进制图像，而不是图像URL，我必须再次提出请求，以获得图像。

$url1 ='https://www.google.com/m8/feeds/photos/media/{useremail}/13444?  v=3.0&oauth_token='.$accesstoken; 
$xmlresponse1 = curl($url1); 

要显示的图像：

<img src="data:image/*;base64,<?php echo base64_encode($xmlresponse1); ?> /> 

我还是不能接触式图像URL类似Facebook的回报？

Answer 1

根据该文件，contactIid在通过API返回的联系人条目URL返回：

http://www.google.com/m8/feeds/contacts/<userEmail>/base/<contactId> 

所以，给你的样品：

http://www.google.com/m8/feeds/contacts/sfdhitdf1%40gmail.com/base/1 

我们有这些值：

userEmail: [email protected] 
contactId: 1