如何在处理ide时合并两个程序以便按顺序运行它们?

问题描述:

我想合并两个程序。一个是播放介绍视频的视频播放器,另一个是显示雷达(我在网上找到了这个编码)。我想要做的是首先播放视频,这是对雷达的介绍,然后显示雷达。雷达显示器与Arduino Mega 2560连接,并有自己的编码。这是两个代码。如何在处理ide时合并两个程序以便按顺序运行它们?

import processing.video.*; 

String PATH = "D:\\FullZord.mp4"; 
Movie mov; 

void setup() 
    { 
    size(1920, 1080); 
    frameRate(30); 
    mov = new Movie(this, PATH); 
    mov.play(); 
    mov.speed(1); 
    mov.volume(10); 
    } 

void movieEvent(Movie m) 
    { 
    m.read(); 
    } 

void draw() 
    { 
    image(mov, 0, 0, width, height); 
    } 

import processing.serial.*; // imports library for serial communication 
import java.awt.event.KeyEvent; // imports library for reading the data from the serial port 
import java.io.IOException; 
Serial myPort; // defines Object Serial 
// defubes variables 
String angle=""; 
String distance=""; 
String data=""; 
String noObject; 
float pixsDistance; 
int iAngle, iDistance; 
int index1=0; 
int index2=0; 
PFont orcFont; 

void setup() 
    { 

    size (1920, 1080); 
    smooth(); 
    myPort = new Serial(this,"COM4", 9600); // starts the serial communication 
    myPort.bufferUntil('.'); // reads the data from the serial port up to the character '.'. So actually it reads this: angle,distance. 
    orcFont = loadFont("OCRAExtended-30.vlw"); 
    } 

void draw() 
    { 

    fill(98,245,31); 
    textFont(orcFont); 
    // simulating motion blur and slow fade of the moving line 
    noStroke(); 
    fill(0,4); 
    rect(0, 0, width, 1010); 

    fill(98,245,31); // green color 
    // calls the functions for drawing the radar 
    drawRadar(); 
    drawLine(); 
    drawObject(); 
    drawText(); 
    } 

void serialEvent (Serial myPort) 
    { // starts reading data from the Serial Port 
// reads the data from the Serial Port up to the character '.' and puts it into the String variable "data". 
    data = myPort.readStringUntil('.'); 
    data = data.substring(0,data.length()-1); 

    index1 = data.indexOf(","); // find the character ',' and puts it into 
    the 
    variable "index1" 
    angle= data.substring(0, index1); // read the data from position "0" to position of the variable index1 or thats the value of the angle the Arduino Board sent into the Serial Port 
    distance= data.substring(index1+1, data.length()); // read the data from position "index1" to the end of the data pr thats the value of the distance 

// converts the String variables into Integer 
    iAngle = int(angle); 
    iDistance = int(distance); 
    } 

void drawRadar() 
    { 
    pushMatrix(); 
    translate(960,1000); // moves the starting coordinats to new location 
    noFill(); 
    strokeWeight(2); 
    stroke(98,245,31); 
// draws the arc lines 
    arc(0,0,1800,1800,PI,TWO_PI); 
    arc(0,0,1400,1400,PI,TWO_PI); 
    arc(0,0,1000,1000,PI,TWO_PI); 
    arc(0,0,600,600,PI,TWO_PI); 
// draws the angle lines 
    line(-960,0,960,0); 
    line(0,0,-960*cos(radians(30)),-960*sin(radians(30))); 
    line(0,0,-960*cos(radians(60)),-960*sin(radians(60))); 
    line(0,0,-960*cos(radians(90)),-960*sin(radians(90))); 
    line(0,0,-960*cos(radians(120)),-960*sin(radians(120))); 
    line(0,0,-960*cos(radians(150)),-960*sin(radians(150))); 
    line(-960*cos(radians(30)),0,960,0); 
    popMatrix(); 
    } 

void drawObject() 
    { 
    pushMatrix(); 
    translate(960,1000); // moves the starting coordinats to new location 
    strokeWeight(9); 
    stroke(255,10,10); // red color 
    pixsDistance = iDistance*22.5; // covers the distance from the sensor from cm to pixels 
// limiting the range to 40 cms 
    if(iDistance<40){ 
// draws the object according to the angle and the distance 
    line(pixsDistance*cos(radians(iAngle)),-pixsDistance*sin(radians(iAngle)),950*cos(radians(iAngle)),-950*sin(radians(iAn 
gle))); 
    } 
    popMatrix(); 
    } 
void drawLine() 
    { 
    pushMatrix(); 
    strokeWeight(9); 
    stroke(30,250,60); 
    translate(960,1000); // moves the starting coordinats to new location 
    line(0,0,950*cos(radians(iAngle)),-950*sin(radians(iAngle))); // draws the line according to the angle 
    popMatrix(); 
    } 

void drawText() 
    { // draws the texts on the screen 

    pushMatrix(); 
    if(iDistance>40) 
     { 
     noObject = "Out of Range"; 
     } 
    else 
     { 
      noObject = "In Range"; 
     } 
    fill(0,0,0); 
    noStroke(); 
    rect(0, 1010, width, 1080); 
    fill(98,245,31); 
    textSize(25); 
    text("10cm",1180,990); 
    text("20cm",1380,990); 
    text("30cm",1580,990); 
    text("40cm",1780,990); 
    textSize(40); 
    text("Object: " + noObject, 240, 1050); 
    text("Angle: " + iAngle +" °", 1050, 1050); 
    text("Distance: ", 1380, 1050); 

    if(iDistance<40) 
     { 
     text("  " + iDistance +" cm", 1400, 1050); 
     } 
    textSize(25); 
    fill(98,245,60); 
    translate(961+960*cos(radians(30)),982-960*sin(radians(30))); 
    rotate(-radians(-60)); 
    text("30°",0,0); 
    resetMatrix(); 
    translate(954+960*cos(radians(60)),984-960*sin(radians(60))); 
    rotate(-radians(-30)); 
    text("60°",0,0); 
    resetMatrix(); 
    translate(945+960*cos(radians(90)),990-960*sin(radians(90))); 
    rotate(radians(0)); 
    text("90°",0,0); 
    resetMatrix(); 
    translate(935+960*cos(radians(120)),1003-960*sin(radians(120))); 
    rotate(radians(-30)); 
    text("120°",0,0); 
    resetMatrix(); 
    translate(940+960*cos(radians(150)),1018-960*sin(radians(150))); 
    rotate(radians(-60)); 
    text("150°",0,0); 
    popMatrix(); 
    } 
+5

你的代码是没有任何压痕使这一切左对齐,几乎是不可能的阅读,理解和调试。请重新格式化发布的代码,方法是给它适当的缩进,通常每块4个空格,并确保同一个块上的所有代码都在相同的缩进级别上。您将非常感谢您的合作,并有可能提高您获得体面和迅速答案的机会。 –

+0

编辑帖子。这是一个处理ide的程序。我认为他们没有主要的方法。 –

+0

哦,对不起,我没有注意到“处理”标签。我认为你的意思是一般意义上的“加工”。 –

你将需要阅读的参考材料视频库。您正在寻找一种检测电影播放时间或停止时间的方法。它可能类似于Movie类中的isPlaying()函数。

当你有,你可以调用,在draw()功能,以检测是否电影仍在播放。如果是这样,绘制它。如果没有,则显示雷达。

但是开始变小。首先,当电影完成播放时,你能打印一些东西给控制台吗?建立起来的。

另外,我强烈建议你不要只使用代码,您从互联网上复制粘贴。这只会让你头痛不已。相反,尝试了解代码正在做什么。否则,将无法进行调试或进行更改。在使用之前,您需要真正了解代码。

+0

谢谢!将尝试一下。 –

解决了!我只是使用了延时功能。这个。

if (millis() > 1000) { 
    // do something 
    } 
+0

这可能会起作用,但它可能不是你想要的。你应该轮询'Movie'实例本身。 –

+0

它工作得很好。我将时间段设置为视频的长度,并且工作得很好。 –

+0

@像我说的那样,它可能工作。但是如果你想使用不同长度的视频会发生什么?我不是说你的方法**是错误的**。我只是说现有的功能会让你的生活更轻松。最终取决于你。没有任何一种正确的方式来做事 - 这就是编码的美妙之处。 –