MongoEngine - 查询 - 如何检查ListField是否为空或未设置
答
import unittest
from mongoengine import *
class Test(unittest.TestCase):
def setUp(self):
conn = connect(db='mongoenginetest')
def test_list_exists_or_has_size(self):
class Post(Document):
title = StringField(required=True)
tags = ListField(StringField())
Post.drop_collection()
Post(title="Hello Stackoverflow").save()
Post(title="Hello twitter", tags=[]).save()
Post(title="Hello world", tags=['post', 'blog']).save()
self.assertEqual(2, Post.objects(
Q(tags__exists=False) |
Q(tags__size=0)).count())
答
不知道完全肯定,如果这是你的空或意思没有设置 ListField这样的:
from mongoengine import *
connect('tumblelog')
class Post(Document):
title = StringField(required=True)
tags = ListField(StringField())
post1 = Post(title='Fun with MongoEngine', tags=['mongodb', 'mongoengine'])
post1.save()
for post in Post.objects:
print post.title
if not post.tags:
print '-post has no tags'
else:
print post.tags
这将输出:
Fun with MongoEngine
[u'mongodb', u'mongoengine']
Fun with MongoEngine no tags
-post has no tags
听起来不错!但在最终查询中它的“存在”而不是“存在”,不是吗?我不允许以少于6个字符的方式进行更改... – Ron 2012-08-14 07:28:27