选择选项，电子邮件表格

Question

我试图让'选择'发布到我的电子邮件，其他输入字段 做后，但不是选择它驱使我坚果。请指教。另外任何 额外的建议，在SQL注入预防方法将不胜感激。

HTML 

<form action="contactform.php" method="post" > 
<input type="text" name="name" placeholder="*Full Name"> 
<input type="text" name="email" placeholder="*Email"> 
<input type="tel" name="telephone"placeholder="*Telephone"> 
<input type="text" name="comments"class="feedback-input"id="comments"placeholder="*How can I help?"> 
<select name="selectoption"> 
    <option value="first">First</option> 
    <option value="second">Second</option> 
    <option value="third">Third</option> 
    </select> 
<input type="text" name="code" placeholder="1+2 =" /> 
<input type="submit"value="Send"class="button"> 
</form> 



PHP 
<?php 

if(isset($_POST['email'])) { 


if (strtolower($_POST['code']) != '3') {die('Wrong access code');} 


    $email_to = ""; 

    $email_subject = "contact form submission"; 

    $name = $_POST['name']; // required 

    $email_from = $_POST['email']; // required 

    $telephone = $_POST['telephone']; // not required 


    $comments = $_POST['comments']; // required 

    $selectoption = $_POST['selectoption']; // required 



    function clean_string($string) { 

     $bad = array("content-type","bcc:","to:","cc:","href"); 

     return str_replace($bad,"",$string); 

    } 

    $email_message .= "Name: ".clean_string($name)."\n"; 

    $email_message .= "Email: ".clean_string($email_from)."\n"; 

    $email_message .= "Telephone: ".clean_string($telephone)."\n"; 


    $email_message .= "Comments: ".clean_string($comments)."\n"; 

    $email_message .= "Selectoption: ".clean_string($selectoption)."\n"; 




// create email headers 

$headers = 'From: '.$email_from."\r\n". 

'Reply-To: '.$email_from."\r\n" . 

'X-Mailer: PHP/' . phpversion(); 

@mail($email_to, $email_subject, $email_message, $headers); 

?> 






Thank you for contacting us. We will be in touch with you very soon. 
<a href="#">return to website</a> 


<?php 

} 

?> 



thanks very much 
Dan 

Answer 1

<select name="selectoption"> 
    <option value="first">First</option> 
    <option value="second">Second</option> 
    <option value="third">Third</option> 
</select> 

可以得到选择的valueBy下面的代码： -

$selectOption = $_POST['selectoption']; 

使用isset检查值存在与否。

$name = isset($_POST['name']) ? $_POST['name'] : ''; 

$email_from = isset($_POST['email']) ? $_POST['email'] : ''; 

$telephone = isset($_POST['telephone']) ? $_POST['telephone'] : '';  

$comments = isset($_POST['comments']) ? $_POST['comments'] : ''; 

$selectoption = isset($_POST['selectoption']) ? $_POST['selectoption'] : ''; 

SQL注入防御技术，

转寄此link。

希望它能帮助你:)