如何处理 - 应用程序已停止在Android中工作
问题描述:
因此,我正在尝试创建一个Android应用程序,它基本上根据UI内的搜索查询读出Twitter提要。我需要从解析的JSON中显示的提要是用户名,句柄,个人资料图片和推文。如何处理 - 应用程序已停止在Android中工作
现在我已经创建了所有东西,并且我的代码编译完成了,但只要我运行它,应用程序就会打开,然后我在搜索Feed中写入内容并敲入回车 - “不幸的是,AppName已停止工作”和我的源代码供参考。
*通过从DoInBackground中删除设置文本解决了该问题,然后给予Android足够的权限以访问互联网。现在的问题是,当我尝试并显示个人资料图片时,显示的是网址,而不是图片。
的源代码:
package com.example.twittersearchactivity;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLEncoder;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.StatusLine;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONObject;
import android.os.AsyncTask;
import android.os.Bundle;
import android.app.Activity;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.drawable.BitmapDrawable;
import android.graphics.drawable.Drawable;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;
public class TwitterSearchActivity extends Activity {
private TextView tweetDisplay;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_twitter_search);
tweetDisplay = (TextView)findViewById(R.id.tweet_txt);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.twitter_search, menu);
return true;
}
public void searchTwitter(View view){
EditText searchTxt = (EditText)findViewById(R.id.search_edit);
String searchTerm = searchTxt.getText().toString();
if(searchTerm.length()>0){
try{
String encodedSearch = URLEncoder.encode(searchTerm, "UTF-8");
String searchURL = "http://search.twitter.com/search.json?q="+encodedSearch;
new GetTweets().execute(searchURL);
Log.i("1", "entered the searchterm");
}
catch(Exception e){
tweetDisplay.setText("Whoops - something went wrong!");
e.printStackTrace();
}
}
else
tweetDisplay.setText("Enter a search query!");
}
private class GetTweets extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... twitterURL) {
StringBuilder tweetFeedBuilder = new StringBuilder();
for (String searchURL : twitterURL) {
HttpClient tweetClient = new DefaultHttpClient();
try {
HttpGet tweetGet = new HttpGet(searchURL);
HttpResponse tweetResponse = tweetClient.execute(tweetGet);
StatusLine searchStatus = tweetResponse.getStatusLine();
if (searchStatus.getStatusCode() == 200) {
HttpEntity tweetEntity = tweetResponse.getEntity();
Log.i("2", "entered gettweets");
InputStream tweetContent = tweetEntity.getContent();
InputStreamReader tweetInput = new InputStreamReader(tweetContent);
BufferedReader tweetReader = new BufferedReader(tweetInput);
String lineIn;
while ((lineIn = tweetReader.readLine()) != null) {
tweetFeedBuilder.append(lineIn);
Log.i("3", "entered while in dobackground");
}
}
else {Log.i("error", "error");}
//tweetDisplay.setText("Whoops - something went wrong!");
}
catch(Exception e) {
Log.e("DEBUGTAG", "Remote Image Exception", e);
//tweetDisplay.setText("Whoops - something went wrong!");
e.printStackTrace();
}}
return tweetFeedBuilder.toString();
}
protected void onPostExecute(String result) {
StringBuilder y;
StringBuilder tweetResultBuilder = new StringBuilder();
try {
Log.i("tag", "entered try block");
JSONObject resultObject = new JSONObject(result);
JSONArray tweetArray = resultObject.getJSONArray("results");
for (int t=0; t<tweetArray.length(); t++) {
Log.i("tag", "entered the json stream");
JSONObject tweetObject = tweetArray.getJSONObject(t);
tweetResultBuilder.append(tweetObject.getString("from_user")+": ");
tweetResultBuilder.append(tweetObject.getString("from_user_name")+": ");
tweetResultBuilder.append(tweetObject.get("text")+"\n\n");
String imageURL = (String) tweetObject.get(("profile_image_url")+": ");
Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL(imageURL).getContent());
@SuppressWarnings("deprecation")
Drawable d =new BitmapDrawable(bitmap);
d.setAlpha(255);
TextView.setCompoundDrawablesWithIntrinsicBounds(0,0,1,0);
}
}
catch (Exception e) {
tweetDisplay.setText("Whoops - something went wrong!");
e.printStackTrace();}
if(tweetResultBuilder.length()>0)
tweetDisplay.setText(tweetResultBuilder.toString());
else
tweetDisplay.setText("Sorry - no tweets found for your search!");
}
}}
答
不能调用像setText
视图功能在另一个线程就像一个AsyncTask
doInBackground
功能。您需要在onPostExecute
中完成。
是否这样做,在AsyncTask doInBackground中同时评论了setText,但现在在搜索查询时,即使Web浏览器中的类似查询显示结果,也只是显示“抱歉,找不到推文”。 – user1795516 2013-02-26 06:57:56
听起来像是一个单独的问题。我会在调试器下运行它,看看哪里出了问题。 – 2013-02-26 06:59:01
logcat for debugger:https://www.dropbox.com/s/du3le8dshr9n090/log.txt – user1795516 2013-02-26 07:10:37