分配错误在作业
问题描述:
我目前正在学习C,我来自java。我们的任务要求我们从可以添加的文件中计算字符串,或者要求用户输入字符串。我们刚开始使用指针,并且查找了段错误发生的不同原因,但我不知道如何检查它是哪个问题。我将所有的指针初始化为NULL,但它仍然不起作用,从我读到的这是发生分段错误的最常见原因。分配错误在作业
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int debug = 0;
int
main(int argc, char **argv)
{
extern char *optarg;
extern int optind;
FILE* infile = NULL;
int c, err = 0;
int lflag = 0, sflag = 0, count = 0; //flags and count
char *shortWord = NULL, *longWord = NULL; //variable for shortest and longest word
int shortest = 100, longest = 0; //longest char 100, shortest 0
char *string = NULL;
char *pch = NULL;
static char usage[] = "usage: %s [-l] [-s] [filename]\n";
while ((c = getopt(argc, argv, "ls")) != -1)
switch (c)
{
case 'l':
lflag = 1;
break;
case 's':
sflag = 1;
break;
case '?':
err = 1;
break;
}
if (err)
{
fprintf(stderr, usage, argv[0]);
exit(1);
}
//checks for file and then runs loop for word count
infile = fopen("myfile.txt","r");
if (infile != NULL)
{
fgets(string, 100, infile);
pch = strtok (string, " ,.-");
while(pch != NULL)
{
count++;
if (strlen(pch) > longest)
longWord = pch;
if (strlen(pch) < shortest)
shortWord = pch;
pch = strtok (NULL, " ,.");
}
}
//else, asks for string
else
{
printf("Enter your string: \n");
fgets(string, 100, stdin);
int len = strlen(string);
count = len;
pch = strtok (string, " ,.-");
while(pch != NULL)
{
count++;
if (strlen(pch) > longest)
longWord = pch;
if (strlen(pch) < shortest)
shortWord = pch;
pch = strtok (NULL, " ,.");
}
}
//following lines compute value based on arguments
if(lflag == 1)
{
printf("Longest word is %s", longWord);
}
if(sflag == 1)
{
printf("Shortest word is %s", shortWord);
}
printf("Word count = %.2d\n", count);
exit(0);
}
答
他们是在你的代码中的一些问题:
- 您初始化
string
到NULL
,然后将其作为fgets()
输入缓冲器。fgets()
重新提供一个指向字符数组的指针,这些字符可以在堆栈中声明或动态分配为malloc(3)
。您可以设置一个输入缓冲区,例如char string[100]
。 -
fgets()
必须检查,因为它无法读取一行时返回NULL
。 -
strtok()
的分隔符不是\n
附加fgets()
的字符。您可以删除此换行符,也可以将其包含在分隔符中。如果您想将其包含在分隔符中,请确保您的分隔符是" ,.-\n"
。 - 您可以使用
strtok()
来创建解析输入的函数,因为这可以使您的main()
更短,并减少代码中的重复性。一个示例函数原型可能是void longest_shortest_words(char line[], char **longest, char **shortest, size_t *word_count);
,您可以通过指针将最长的最短单词连同单词的数量一起传递回main()
。您也可以将最长和最短的单词存储在二维数组或指针数组中。 -
您还应该明确检查您的文件是否已正确打开。像这样的东西应该包括:
infile = fopen("myfile.txt", "r"); if (infile == NULL) { fprintf(stderr, "Failed to open file\n"); exit(EXIT_FAILURE); }
-
当检查
opt
,在switch语句检查?
作为一个字符是不正确的。而不是:case '?': err = 1; break;
使用
default
,它涵盖输入的任何其他无效选项。这里是你如何使用它:default: fprintf(stderr, "usage: %s [-l] [-s] [filename]\n", argv[0]); exit(EXIT_FAILURE);
检查末
sflag
和lflag
是不够的。您应该检查是否longWord
和shortWord
不是NULL
。
下面是一些示例代码,这表明以下几点:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#define LINESIZE 100
void longest_shortest_words(char line[], char **longest, char **shortest, size_t *wordcount);
void print_output(int lflag, int sflag, char *longword, char *shortword, size_t wordcount);
void remove_newline(char line[]);
int main(int argc, char * const argv[]) {
FILE *infile;
char line[LINESIZE] = {'\0'};
int opt, sflag = 0, lflag = 0;
size_t wordcount = 0;
const char *optstr = "ls";
char *longword = NULL, *shortword = NULL;
while ((opt = getopt(argc, argv, optstr)) != -1) {
switch(opt) {
case 'l':
lflag = 1;
break;
case 's':
sflag = 1;
break;
default:
fprintf(stderr, "usage: %s [-l] [-s] [filename]\n", argv[0]);
exit(EXIT_FAILURE);
}
}
/* Checking if file is in directory */
infile = fopen("myfile.txt", "r");
if (infile == NULL) {
fprintf(stderr, "Failed to open file\n");
exit(EXIT_FAILURE);
}
/* checking if line exists in file */
if (fgets(line, LINESIZE, infile) == NULL) {
fprintf(stderr, "No line found in file.\n");
printf("\nEnter string instead:\n");
if (fgets(line, LINESIZE, stdin) != NULL) {
remove_newline(line);
longest_shortest_words(line, &longword, &shortword, &wordcount);
/* checking that longWord, shortWord and word_count are valid */
if (longword != NULL && shortword != NULL && wordcount > 0) {
print_output(lflag, sflag, longword, shortword, wordcount);
}
}
/* file has line, do stuff with it */
} else {
remove_newline(line);
longest_shortest_words(line, &longword, &shortword, &wordcount);
print_output(lflag, sflag, longword, shortword, wordcount);
}
exit(EXIT_SUCCESS);
}
/* function for printing output, can be improved */
void print_output(int lflag, int sflag, char *longword, char *shortword, size_t wordcount) {
if (lflag) {
printf("Longest word: %s\n", longword);
}
if (sflag) {
printf("Shortest word: %s\n", shortword);
}
if (wordcount > 0) {
printf("Word count = %zu\n", wordcount);
}
}
/* function for removing newline, and checking that input hasnt exceeded limit */
void remove_newline(char line[]) {
size_t slen;
slen = strlen(line);
if (slen > 0 && line[slen-1] == '\n') {
line[slen-1] = '\0';
} else {
fprintf(stderr, "\nToo many characters in input.\n");
exit(EXIT_FAILURE);
}
}
/* function which parses line, and saves longWord and shortWord in pointers */
void longest_shortest_words(char line[], char **longword, char **shortword, size_t *wordcount) {
char *word = NULL;
const char *delim = " ,.";
word = strtok(line, delim);
if (word != NULL) {
*longword = word;
*shortword = word;
*wordcount = 1;
}
while ((word = strtok(NULL, delim)) != NULL) {
(*wordcount)++;
if (strlen(word) > strlen(*longword)) {
*longword = word;
} else if (strlen(word) < strlen(*shortword)) {
*shortword = word;
}
}
}
注:上面显示的代码可以改善,它只是告诉你另一种方法,您的问题。
你认为传入'main()'的int argc'的目的可能是什么? –
建议您使用调试器。这是正确的工具,你将从学习中受益。 – kaylum
“将我的所有指针初始化为NULL”。尽管你认为你读过,但这不是解决seg故障的方法。 *访问* NULL指针是seg故障的常见原因。这正是你的'string'变量的价值所在。 – kaylum