发送电子邮件和写入数据库不工作
问题描述:
我有一个表格,允许非用户的消息,脚本采取的形式内容,将它们存储在我的messages
表中,然后最终通过电子邮件发送给用户的内容他们的电邮地址。发送电子邮件和写入数据库不工作
我很难弄清楚为什么我的表单不会提交并返回错误信息,我没有正确地完成设置。没有电子邮件正在发送,并且没有正在进行的数据库表中。
我的表单代码;
<form class="signup-form" action="sendmail.php" id="email_submit" method="POST">
<fieldset>
<input type="text" name="msg_touserid" id="msg_touserid" value="<?php echo htmlentities($_GET["uid"], ENT_QUOTES, 'UTF-8'); ?>" style="display: none;">
<input type="text" name="msg_tousername" id="msg_tousername" value="<?php echo htmlentities($_GET["username"], ENT_QUOTES, 'UTF-8'); ?>" style="display: none;">
<input type="text" placeholder="Your name..." name="msg_fromname" id="msg_fromname" value=""><br />
<input type="text" placeholder="Your mobile number..." name="msg_mobile" id="msg_mobile" value=""><br />
<input type="email" name="msg_toemail" id="msg_toemail" value="[email protected]" style="display: none;">
<input type="email" placeholder="Your email..." name="msg_fromemail" id="msg_fromemail" value=""><br />
<input type="text" placeholder="Message subject..." name="msg_subject" id="msg_subject" value=""><br />
<textarea name="msg_messagebody" id="msg_messagebody" style="height: 282px; background-image: none; background-position: 0px 50%; background-repeat: repeat;"></textarea>
</fieldset>
<input type="submit" class="btn-colored submit-send-email" value="Send email" />
</form>
我的sendmail.php代码;
$connection = mysql_connect('localhost', 'XXX', 'XXX');
if (!$connection){
die('Could not connect: ' . mysql_error());
}
mysql_select_db('DB');
if (isset($_POST['email_submit'])){
$msg_touserid = $_POST['msg_touserid'];
$msg_tousername = $_POST['msg_tousername'];
$msg_fromname = $_POST['msg_fromname'];
$msg_mobile = $_POST['msg_mobile'];
$msg_toemail = $_POST['msg_toemail'];
$msg_fromemail = $_POST['msg_fromemail'];
$msg_subject = $_POST['msg_subject'];
$msg_messagebody = $_POST['msg_messagebody'];
$sql = "INSERT INTO messages (msg_touserid, msg_tousername, msg_fromname, msg_mobile, msg_toemail, msg_fromemail, msg_subject, msg_messagebody)
VALUES ('$msg_touserid', $msg_tousername', '$msg_fromname', '$msg_mobile', '$msg_toemail', '$msg_fromemail', '$msg_subject', '$msg_messagebody')";
if (!mysql_query($sql,$connection)){
die('Error: ' . mysql_error());
}
$emailID = "$msg_toemail";
$subject = "Enquiry from. $msg_fromname . through our website";
$body = <<<EOD
<table cellspacing="0" cellpadding="1" border="1">
<tbody>
<tr>
<td style="padding: 5px 10px;" width="150">Name: </td>
<td style="padding: 5px 10px;">$msg_fromname</td>
</tr>
<tr>
<td style="padding: 5px 10px;" width="150">Mobile: </td>
<td style="padding: 5px 10px;">$msg_mobile</td>
</tr>
<tr>
<td style="padding: 5px 10px;" width="150">Email: </td>
<td style="padding: 5px 10px;">$msg_fromemail</td>
</tr>
<tr>
<td style="padding: 5px 10px;" width="150">Message: </td>
<td style="padding: 5px 10px;">$msg_messagebody</td>
</tr>
</tbody>
</table>
EOD;
$headers = "From: [email protected]\r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=\"iso-8859-1\"\n";
$headers .= "X-Priority: 1\r\n";
$headers .= "X-MSMail-Priority: High\n";
$headers .= "X-Mailer: PHP". phpversion() ."\r\n";
mail($emailID, $subject, $body, $headers);
echo "<h4>Thank you for your message.</h4>";
} else {
echo("Oops... Please check you have completed the form correctly.");
};
我的数据库结构;
id int(10) (AI)
msg_touserid int(10)
msg_tousername varchar(100)
msg_fromname varchar(100)
msg_mobile varchar(20)
msg_toemail varchar(100)
msg_fromemail varchar(100)
msg_subject varchar(200)
msg_messagebody varchar(1000)
msg_sent timestamp
答
提交按钮没有name
属性。
<input type="submit" class="btn-colored submit-send-email" value="Send email" />
因此,condtion
if (isset($_POST['email_submit'])){
是不令人满意的。
解决方案:
添加name
提交按钮。
更正代码:
<input type="submit" class="btn-colored submit-send-email" value="Send email" name="email_submit" />
+0
谢谢。这似乎已经取得了进展,但后来我意识到我错过了一个数据库的选择,所以我添加了它,但现在得到一个语法错误。我已经更新了上面的sendmail.php代码以反映更改。 –
答
这不是提交/发送电子邮件,因为它从未有过的机会。
if (isset($_POST['email_submit'])){
永远不会满足的email_submit
没有在您的形式定义。您将其设置为表格ID ,但ID不会以与name
相同的方式传递给$_POST
。
给你的提交按钮的email_submit
的名称在您的形式:
<input name="email_submit" type="submit" class="btn-colored submit-send-email" value="Send email">
既然初始条件将满足。
'if(isset($ _ POST ['email_submit'])){...}'永远不会启动,并且http://php.net/manual/en/function.error-reporting.php本来会告诉你的;-) –
[** SQL注入警报**](http://*.com/q/60174/) –