调用未定义的方法PHP错误

Question

我有一个叫CHCID类在其内部具有两个功能：

public function UpdateDeliveryAddress($orderNumber, $deliveryaddress) { 

    $sql = "UPDATE `CIDOrders` 

    SET `DeliveryAddress` = '" . mysql_real_escape_string($deliveryaddress) . "' 

    WHERE `CIDOrderNumber` = " . $orderNumber . ";"; 

    mysql_select_db(DB_DATABASE_NAME, $this->conn); 

    return mysql_query($sql, $this->conn); 

} 

public function UpdateInvoiceAddress($orderNumber, $invoiceAddress) { 

    $sql = "UPDATE `CIDOrders` 

    SET `InvoiceAddress` = '" . mysql_real_escape_string($invoiceaddress) . "' 

    WHERE `CIDOrderNumber` = " . $orderNumber . ";"; 

    mysql_select_db(DB_DATABASE_NAME, $this->conn); 

    return mysql_query($sql, $this->conn); 

} 

我调用这个类中有一个网页叫做createorder.php如下：

// Add a new delivery address to the order 

$cid->UpdateDeliveryAddress($_POST['orderNumber'], $_POST['deliveryaddress']); 

// Add invoice address to the order 

$cid->UpdateInvoiceAddress($_POST['orderNumber'], $_POST['invoiceaddress']); 

我收到以下错误：

PHP Fatal error: Call to undefined method CHCID::UpdateDeliveryAddress() 

任何人都可以帮忙。

非常感谢

初始化类的代码。

require_once $CID_INCLUDE_PATH . "/cid.php"; 

$cid = new CHCID(); 

建设类

class CHCID { 



    var $conn; 



    // Constructor, connect to the database 

    public function __construct() { 

     require_once "/var/www/reporting/settings.php"; 

     if(!$this->conn = mysql_connect(DB_HOST, DB_USERNAME, DB_PASSWORD)) die(mysql_error()); 

     if(!mysql_select_db(DB_DATABASE_NAME, $this->conn)) die(mysql_error()); 

    } 

Answer 1

如果这些功能真的在你的班级，这永远不会发生。

检查$CID_INCLUDE_PATH，你可能正在加载一个不同的文件，也许是一个旧版本的类。还可以启用警告，通知...