Mysql的总和除以一个月的过去12个月
问题描述:
你好,我用这个SQL查询来获取基于每月的图表表示在过去12次月的记录:Mysql的总和除以一个月的过去12个月
SELECT DATE_FORMAT(drives.timestamp, "%b") AS Month,
DATE_FORMAT(drives.timestamp, "%d-%m-%Y %H:%i:%s") AS Exact_date,
drives.departure,
drives.destination,
drives.route,
CONCAT(drivers.name, " ", drivers.surname) as driver,
drivers.id as driver_id
FROM drives, drivers WHERE drives.driver = drivers.id
AND drives.timestamp > DATE_SUB(now(), INTERVAL 12 MONTH) ORDER BY drives.timestamp Asc
然而
如果没有记录一个月没有按预期包含在结果集中,而且我正在用php做很多计算来实现我想要的结果。
我的问题是这样的:有没有办法在过去12个月中检索每月驱动器总和的简单结果集,并且如果一个月内有0个驱动器,则它必须也包括在内 - 显示在结果集。
答
您需要使用包含每个月的行的表进行外连接。假设你没有这样的表,你可以在飞行中使用硬编码的UNION查询创建:
SELECT * FROM
(SELECT DATE_FORMAT(now(), "%b") as Month
UNION
SELECT DATE_FORMAT(now() - INTERVAL 1 MONTH), "%b")
UNION
SELECT DATE_FORMAT(now() - INTERVAL 2 MONTH), "%b")
UNION
...
SELECT DATE_FORMAT(now() - INTERVAL 11 MONTH), "%b")) AS Months
LEFT JOIN (SELECT DATE_FORMAT(drives.timestamp, "%b") AS Month,
drives.timestamp,
DATE_FORMAT(drives.timestamp, "%d-%m-%Y %H:%i:%s") AS Exact_date,
drives.departure,
drives.destination,
drives.route,
CONCAT(drivers.name, " ", drivers.surname) as driver,
drivers.id as driver_id
FROM drives, drivers WHERE drives.driver = drivers.id
AND drives.timestamp > DATE_SUB(now(), INTERVAL 12 MONTH)) data
ON Months.Month = data.Month
ORDER BY data.timestamp
没有记录任何个月内将有一个排,在数据列NULL
。