如何总结matlab中neigburs的价值？

Question

我是matlab新手，试图编写生活游戏。但是，我有一些困难，造成了neigbors的总和。每个单元格可以有0或1的值。我正在尝试使用一个计数器（就像在Python中，这是我所熟悉的唯一程序），但似乎并不奏效。问题是必须适用于所有单元格，所以边界单元格也适用。如果我有每个细胞的价值（所​​以这将介于0和8之间），我必须执行规则。但我也不知道这是否正确。请帮忙！我越来越绝望了！

TIME = 50; 


pulsar; 

life = {}; % create list 'life' 
life{1} = X; % add seed to life 

numrows = size(X,1); % calculate number of rows 
numcolumns = size (X,2); % calculate number of columns 

current = X;   % make seed the first current(matrix you're starting off with in each step) 

for i = 0:TIME; % determine amount of times the loop will run 

for row = 1:numrows;    % for each row 
    for column = 1:numcolumns; % for each column 

if column + 1 ~= numcolumns + 1 
east_of_row = column + 1; % define how to count the cell right of target cell 
end 
if column - 1 ~= 0 
west_of_row = column - 1; % define how to count the cell left of target cell  
end 
if row - 1 ~= 0 
north_of_column = row - 1; % define how to count the cell north of target cell  
end 
if row + 1 ~= numrows + 1 
south_of_column = row + 1; 
end 

    neighbors = 0        % start counter 'neighbors' with 0 

      if current(row,east_of_row) == 1;    % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(row,west_of_row) == 1;    % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(north_of_column,column) == 1;  % if neighboring cell has a value of 1  
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(south_of_column,column) == 1;  % if neighboring cell has a value of 1  
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(south_of_column,east_of_row) == 1; % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(north_of_column,east_of_row) == 1; % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(north_of_column,west_of_row) == 1; % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors 
      end 
      if current(south_of_column,west_of_row) == 1; % if neighboring cell has a value of 1 
       neighbors = neighbors + 1;         % add 1 to neighbors  
      end 


     % rules of the game: 

    if current(row,column) == 1;    % in case a target cell has a value of 1: 

     if neighbors < 2       % if the number of neighbors is smaller than 2 
      nextnext(row,column) = 0;     % value of target cell gets 0 in nextnext 
     end 
     if neighbors == 2      % if the number of neighbors is 2 or 3 
      nextnext(row,column) = 1;     % value of target cell stays 1 in nextnext 
     end 
     if neighbors == 3 
      nextnext(row,column) = 1; 
     end 
     if neighbors > 3      % if the number of neigbors is higher than 3 
      nextnext(row,column) = 0;     % value of target cell gets 0 in nextnext 
     end 
    end 
    if current (row,column) == 0   % in case a target cell has a value of 0: 

     if neighbors == 3       % if the number of neighbors is 3 
      nextnext(row,column) = 1;     % value of target cell gets 1 in nextnext 
     end 
     if neighbors ~= 3      % if the number of neigbors isn't 3 
      nextnext(row,column) = 0;     % value of target cell stays 0 in nextnext 
     end 
end 
    end 
end 


current = nextnext;  % make nextnext matrix the current matrix for the next step 
%life{TIME} = nextnext; % add matrix to list 'life 

end 



show(life); 

Answer 1

您可以使用conv2来计算这个值，如下所示：

%First create some example matrix 
% (this is a 5 x 5 matrix with 30% 1's, 70% 0's 
x = full(ceil(sprand(5,5,0.3))) 

%Create your convolution kernal 
% This will add up all the values in the 8 elements surrounding the 
% central element 
k = [1 1 1; 1 0 1; 1 1 1]; 

%Now do the copnvulution (using the 'same' argument to select an output 
%the same size as the input.) 
counts = conv2(x,k,'same') 

这将每次产生轻微不同的例子。但是对于上面代码的执行，我得到以下内容：

x = 
    0  1  0  1  0 
    0  1  0  1  0 
    0  0  1  1  0 
    0  1  0  1  0 
    0  0  0  0  0 

counts = 
    2  1  4  1  2 
    2  2  6  3  3 
    2  3  5  3  3 
    1  1  4  2  2 
    1  1  2  1  1