PHP树枝条件筛选

Question

比方说，我有这样的事情：

<img src='{{ asset(article.image.path) | imagine_filter('watermarked') }}' />

我想要做的是应用imagine_filter('watermarked')只有article.isWatermarked()等于true。

有没有这样做的切片方式？或者我坚持

{% set src = asset(article.image.path) %} 
{% if article.isWatermarked() %} 
{% set src = asset(article.image.path) | imagine_filter('watermarked') %} 
{% endif %} 
<img src='{{ src }}' /> 

Answer 1

这应该工作

<img src='{{ article.isWatermarked() ? asset(article.image.path) | imagine_filter('watermarked') : asset(article.image.path) }}' /> 

见三元运营商DOC：https://twig.sensiolabs.org/doc/2.x/templates.html#other-operators

Answer 2

取决于你有多少地方需要该功能的，你可以把它放在一个宏：

macros.twig：

{%- macro wmImage(article) -%} 
    {%- set src = article.watermarked ? asset(article.image.path) | imagine_filter('watermarked') : asset(article.image.path) -%} 
    <img src="{{ src }}"/> 
{%- endmacro -%} 

在模板（S）：

{%- import 'macros.twig' as 'macros' -%} 

Usage: 
{{ macros.wmImage(article) }}