的javascript传递参数的对象

Question

对不起，我这样的新手甚至不完全了解，即使经过观看大量视频和寻找在计算器这么难，甚至无法正常找到我的问题（与不同的对象传递的参数？）所以我在这里只会显示我的代码。

var Test1 = function(name,gender,job) { 
    this.name = name; 
    this.gender = gender; 
    this.job = job; 
this.say = function(name ,gender, job){ 
    console.log(" sup "+ name +", goodluck in" + job); 
    } 
} 

这是new object：

var budi = new Test1('Budi', 'male', 'developer'); 
var tono = new Test1('Tono', 'male', 'chef'); 

和我想通过argument与object：

budi.say(tono); 

Answer 1

你可以任选的say()

this.say = function(person){ 
    console.log(" sup "+ person.name +", goodluck in" + person.job); 
    } 

这或实行调用它喜欢：

budi.say(tono.name, null, tono.job) 

Answer 2

在say()方法读取所述方法参数的name和job（ person在我的例子中）：

var Test1 = function(name, gender, job) { 
 
    this.name = name; 
 
    this.gender = gender; 
 
    this.job = job; 
 
    this.say = function(person) { 
 
    console.log("sup " + person.name + ", good luck in " + person.job); 
 
    } 
 
} 
 

 
var budi = new Test1('Budi', 'male', 'developer'); 
 
var tono = new Test1('Tono', 'male', 'chef'); 
 

 
budi.say(tono);

Answer 3

你可能想要做的，而不是

this.say = function(/*no arguments here*/){ 
    console.log(" sup "+ this.name +", goodluck in" + this.job); 
} 

如果你把同一个名字参数不同的范围，它们将被视为不同的变量。这样你可以这样做：

var budi = new Test1('Budi', 'male', 'developer'); 
budi.say(); 

，它会正确地显示你在构造函数中使用的字符串。

Answer 4

喜请查看这个

//i change it just for convenient:) 
 
var People = function(name, gender, job) { 
 
    this.name = name; 
 
    this.gender = gender; 
 
    this.job = job; 
 
    /* you want your `say` function to call another People 
 
    so pass People as the arg, Object with name, gender, job, and another say method*/ 
 
    this.say = function(p) { 
 
    /* for string i'd like to use backtick(`) for simplicity and less error phone (ex, space, etc)*/ 
 
    console.log(`sup ${p.name}, goodluck in ${p.job}`); 
 
    } 
 
} 
 

 
var budi = new People('Budi', 'male', 'developer'); 
 
var tono = new People('Tono', 'male', 'chef'); 
 

 
budi.say(tono);