自动完成文本框出错
问题描述:
我需要自动完成文本框。我试着下面的代码段:自动完成文本框出错
<input type="text" id="tbx_srchByFn" class="autosuggest" disabled="disabled" value="fieldname" runat="server"
onclick="this.value=''" />
jQuery的
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/themes/base/jquery-ui.css"
rel="stylesheet" type="text/css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/jquery-ui.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
SearchText();
});
function SearchText() {
$(".autosuggest").autocomplete({
source: function (request, response) {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "DDL_Home.aspx/GetAutoCompleteData",
data: "{'username':'" + document.getElementById('tbx_srchByFn').value + "'}",
dataType: "json",
success: function (data) {
response(data.d);
},
error: function (result) {
alert("Error");
}
});
}
});
}
</script>
.cs文件
using System.Web.Services;
[WebMethod]
public static List<string> GetAutoCompleteData(string username)
{
List<string> result = new List<string>();
using (SqlConnection con = new SqlConnection("constr"))
{
using (SqlCommand cmd = new SqlCommand("select DISTINCT Name from Register where Name LIKE '%'[email protected]+'%'", con))
{
con.Open();
cmd.Parameters.AddWithValue("@SearchText", username);
SqlDataReader dr = cmd.ExecuteReader();
while (dr.Read())
{
result.Add(dr["Name"].ToString());
}
return result;
}
}
}
,当我在文本框中键入我没有得到output.but当我删除runat =“server”它的工作原理。我只需要在服务器上,以便我可以从服务器采取文本框的值
答
当我删除runat =“服务器”它的工作原理。
我认为回发发生在您的代码中。所以你必须重新绑定SearchText()
函数。在您的代码中添加以下javascript
。
尝试此代码:
var prm_lp = Sys.WebForms.PageRequestManager.getInstance();
//Re-bind for callbacks
prm_lp.add_endRequest(function() {
SearchText();
});
插入HTML文本框的值作为后面字符串名称=的Request.Form [ “名称”]的代码; – Wenson
http://www.aspsnippets.com/Articles/Get-value-of-HTML-Input-TextBox-in-ASPNet-code-behind-using-C-and-VBNet.aspx – Wenson
添加runat =“server”和检查我的解决方案 – RajeeshMenoth