积分计算器不会工作，当给定的公式给定超过1 x的公式
问题描述：
所以我现在正在积分计算器，它工作得很好，尽管只要将y定义为x ** 2 + x * 2 + 2停止工作。是什么促使我的程序使用y = x ** 2 + 2而不是y = x ** 2 + x * 2 + 2？积分计算器不会工作，当给定的公式给定超过1 x的公式
import math as math
x0 = 0
x1 = 0
def func(y, x):
return eval(y)
def func2(z, x):
return eval(z)
def func3(c, d):
a = 0.0
for i in range(1, n+1):
x0 = a + (i-1) * dx
Ai = dx * (c + d)/ 2.
a = a + Ai
return a
y = str(raw_input("Function 1: "))
z = str(raw_input("Function 2: "))
a = float(input("Left boundary: "))
b = float(input("Right boundary: "))
dx = float(input("Trapezoid width: "))
n = int((b - a)/dx)
Area2 = func3(func(y, x0), func(y, x1))
Area3 = func3(func2(z, x0), func2(z, x1))
Area4 = Area2 - Area3
if Area4 < 0:
Area4 = Area3 - Area2
print "Area = ", Area4
答
import math as math
x0 = 0
x1 = 0
def f(function, x):
function = eval(function)
return function
def func3(b, a, func):
area = 0.0
dx = (b - a)/n
for i in range(1, n+1):
x0 = a + (i-1) * dx
x1 = a + i*dx
Ai = dx * (f(func, x0) + f(func, x1))/ 2.
area = area + Ai
return area
y = str(input("Function 1: "))
z = str(input("Function 2: "))
a = float(input("Left boundary: "))
b = float(input("Right boundary: "))
n = int(input("Trapezoid width: "))
Area2 = func3(b, a, y)
Area3 = func3(b, a, z)
Area4 = Area2 - Area3
if Area4 < 0:
Area4 = Area3 - Area2
print "Area = ", Area4
这是或多或少你想要做什么？
这是不明确的，你需要什么，请修改。 –
从何种意义上说它不清楚？我要求有人弄清楚为什么它会给我正确的结果：y = x \ ** 2 + 2 z = x \ ** 2但是对于y = x \ ** 2 + 2x + 2 z = x \ ** 2 – Meh
@Meh您是否尝试过调试您的代码？ – nemo