替换字符串数组中的最后一个字母Javascript
问题描述:
我需要做如下操作:替换字符串数组中的最后一个字母Javascript
我有一个包含姓氏的字符串数组。其中一些以字母'i'结尾。
manLastNames = [“testowski”,“bucz”,“idzikowski”,“gosz”];
我需要做一个函数来迭代这个字符串数组,如果有一个以'i'结尾的元素,我需要用'i'代替'a',否则只是留下字符串,因为它是。
最后,我想有另一个数组,最后所有'我'被替换为'a'。
womanLastNames = [“testowska”,“bucz”,“idzikowska”,“gosz”];
这是我现在,但是我敢肯定,它开始被垃圾在某些时候
var rep = function() {
var manLastNames = ["testowski","bucz","idzkowski","gosz"];
var womanLastNames = new Array(4);
for (var i=0; i<manLastNames.length; i++) {
var lastName = manLastNames[i];
if (lastName.substr(lastName.length - 1, 1) == 'i') {
lastName = lastName.substr(0, lastName.length - 1) + 'a';
}
}
for (var i=0; i<womanLastNames.length; i++) {
womanLastNames[i] = lastName[i];
}
console.log(womanLastNames);
}
rep();
答
这里是解决
var rep = function() {
var manLastNames = ["testowski","bucz","idzkowski","gosz"];
var womanLastNames =[];
for (var i=0; i<manLastNames.length; i++) {
var lastName = manLastNames[i];
if (lastName.charAt(lastName.length - 1) == 'i') {
lastName = lastName.substr(0, lastName.length - 1) + 'a';
}
womanLastNames.push(lastName);
}
console.log(womanLastNames);
}
rep();
另一种解决方案是使用.map
方法就是这样,用一个回调函数:
var manLastNames = ["testowski","bucz","idzikowski","gosz"];
function mapNames(item){
return item[item.length-1]=='i' ? item.substr(0, item.length-1) + "a" : item;
}
console.log(manLastNames.map(mapNames));
答
尝试代码:
var manNames = ["testowski","bucz","idzkowski","gosz"];
var womanNames = manNames.map(function(name) {
return name.endsWith("i") ? name.slice(0, -1) + "a" : name;
});
console.log(womanNames)
如果你的解释支持ES6,下面是等效的:
names.map((name)=>name.endsWith("i") ? name.slice(0, -1) + "a" : name)
答
这应该工作:
var rep = function() {
var manLastNames = ["testowski","bucz","idzkowski","gosz"];
var womanLastNames = manLastNames;
for(var i=0; i<manLastNames.length;i++){
if(manLastNames[i].charAt(manLastNames[i].length-1)=='i'){
womanLastNames[i]=manLastNames[i].substr(0,womanLastNames[i].length-1)+'a';
}
}
console.log(womanLastNames);
}
rep();
答
取决于你需要如何高效的是,你可以使用正则表达式来完成这两项任务:
var new_name = name.replace(/i$/, 'a');
将取代过去的“我”与“一”,如果一个字符串它存在
var new_name = name.replace(/i/g, 'a');
将用“a”替换字符串中的所有“i”。
var names = ["testowski", "bucz", "idzkowski", "gosz"];
console.log("original", names);
var last_i_replaced = names.map(function(name) {
return name.replace(/i$/, 'a');
});
console.log("last 'i' replaced", last_i_replaced);
var all_i_replaced = names.map(function(name) {
return name.replace(/i/g, 'a');
});
console.log("all 'i's replaced", all_i_replaced);
答
这里是另一种解决方案
var manLastNames = ["testowski","bucz","idzkowski","gosz"];
var womanLastNames = []
manLastNames.forEach(x => {
if (x.charAt(x.length-1) === "i") womanLastNames.push(x.slice(0,-1).concat("a"));
else womanLastNames.push(x);
});
console.log(womanLastNames);
[如何更换在JavaScript字符串的所有出现?(HTTP的可能重复:// *.com/questions/1144783/how-to-replace-all-occurrences-of-a-string-in-javascript) –