用Python解析'时间字符串'？

Question

我正在写涉及使用户按以下格式输入时间的应用程序：

1m30s # 1 Minute, 30 Seconds 

3m15s # 3 Minutes, 15 Seconds 

2m25s # 2 Minutes, 25 Seconds 

2m # 2 Minutes 

55s # 55 Seconds 

的数据可以有一个“分型号”单个“第二名称”，或两者兼而有之。什么是正确的方法来解析这些字符串到类似的格式：

{ 
    "minutes" : 3 
    "seconds" : 25 
} 

Answer 1

import re 

tests=['1m30s','3m15s','2m25s','2m','55s'] 
for time_str in tests: 
    match=re.match('(?:(\d*)m)?(?:(\d*)s)?',time_str) 
    if match: 
     minutes = int(match.group(1) or 0) 
     seconds = int(match.group(2) or 0) 
     print({'minutes':minutes, 
       'seconds':seconds}) 

# {'seconds': 30, 'minutes': 1} 
# {'seconds': 15, 'minutes': 3} 
# {'seconds': 25, 'minutes': 2} 
# {'seconds': 0, 'minutes': 2} 
# {'seconds': 55, 'minutes': 0} 

Answer 2

正则表达式来拯救！

>>> import re 
>>> minsec = re.compile(r'(?P<minutes>\d+)m(?P<seconds>\d+)s') 
>>> result = minsec.match('1m30s')   
>>> result.groupdict() 
{'seconds': '30', 'minutes': '1'} 

编辑：这里是一个修改后的解决方案：

import re 
pattern = r'(?:(?P<minutes>\d+)m)?(?:(?P<seconds>\d+)s)?' 

minsec = re.compile(pattern) 

def parse(s, pat=minsec): 
    return pat.match(s).groupdict() 

tests = ['1m30s', '30s', '10m29s'] 
for t in tests: 
    print '---' 
    print ' in:', t 
    print 'out:', parse(t) 

输出：

--- 
in: 1m30s 
out: {'seconds': '30', 'minutes': '1'} 
--- 
in: 30s 
out: {'seconds': '30', 'minutes': None} 
--- 
in: 10m29s 
out: {'seconds': '29', 'minutes': '10'}