Powershell：从下一行抓取字符，直到特定数量的字符

Question

我有一个文本文件，每行80个字符后将其余字符推送到下一行。所以我想看看如何创建一个逻辑，只有当第一行有80个字符时，我才能从下一行捕获下一个48个字符。

例子（注：堆栈只允许每行76个字符，但同样的想法）

示例文件：

This is a test where I would like this entire line and everything that will 
be g 
oing to this line up until character 48.     08/31/2017 

所以基本上我的变量将举行以下：

This is a test where I would like this entire line and everything that will 
be going to this line up until character 48. 

这是我现在的代码启动逻辑：

$lineArray = Get-Content "c:\sample.txt" 
ForEach ($line in $lineArray) 
If ($line.length -eq 80) {Write-Host $line.length " - Max characters 
Reached"} 
else {Write-Host $line.length " - Within Limits"} 
} 

感谢

Answer 1

对于任何人好奇......我是能够通过使用下面的代码来完成它：

$lineArray = Get-Content "C:\sample.txt" 
$lineNumber = 0 

ForEach ($line in $lineArray) 
{#Write-Host $line.length 

    If ($line.length -eq 80) 
    {#Write-Host $line.length " - Max characters Reached" 
    $nextLine = $lineArray[$lineNumber +1] 
    $retrieve48 = $nextLine.substring(0,48) 
    $newLine = $line + $retrieve48 
    Write-Host = $newLine 
    } 
    else {Write-Host $line.length " - Within Limits"} 
    $lineNumber++ 
    }