让用户输入创建对象

问题描述：

我正在写这个程序，用户需要进行数学测试。我现在面临的并一直在努力解决的问题是如何在测试结束时显示最终得分。让用户输入创建对象

我有一个计数器，每个正确答案的分数都是递增的，但我如何（最后）显示最终/总分？任何帮助表示赞赏。

这是三类btw之一。

import java.util.Scanner; 

public class Questions { 

Scanner scan = new Scanner(System.in); 

int answer = 0; 
int point = 0; 
String correct = "Correct"; 

public void pointers(){  
    point++; 
    System.out.println(point + " point added to total score"); 
} 

public void totalPoints(){ 
    pointers(); 
} 

public void showQuestions(){ 

     System.out.println("\n--------------\nQuestion #1: 1+1 = ? "); 
     answer = scan.nextInt(); 

     if(answer == 2){ 
      System.out.println(correct); 
      pointers(); 
     }else{ 
      System.out.println("Wrong!"); 
     } 

     System.out.println("\nQuestion #2: 340-23 = ? "); 
     answer = scan.nextInt(); 
      if(answer == 317){ 
        System.out.println("Correct!"); 
        pointers(); 
      }else{ 
       System.out.println("Wrong!"); 
      } 

     System.out.println("\nQuestion #3: 900/3 = ? "); 
     answer = scan.nextInt(); 
      if(answer == 300){ 
       System.out.println("Correct!"); 
       pointers(); 
      }else{ 
       System.out.println("Wrong!"); 
      } 

     System.out.println("\nQuestion #4: 23*2 = ? "); 
     answer = scan.nextInt(); 
      if(answer == 46){ 
       System.out.println("Correct!"); 
       pointers(); 
      }else{ 
       System.out.println("Wrong!"); 
      } 

     System.out.println("\nQuestion #5: -4+6 = ? "); 
     answer = scan.nextInt(); 
      if(answer == 2){ 
       System.out.println("Correct!"); 
       pointers(); 
      }else{ 
       System.out.println("Wrong!"); 
      } 


} 
}

答

不知道你试图实现什么，但

进口java.util.Scanner的;

公共类主要{

public static void main(String[] args) { 
    final Scanner keyboard = new Scanner(System.in); 
    System.out.println("Hello, it is time to take a math test.\nFirst we need you to enter some information about yourself."); 

    System.out.print("\nEnter name: "); 
    final String name = keyboard.nextLine(); 
    System.out.print("Enter Age: "); 
    final int age = keyboard.nextInt(); 
    keyboard.close(); 
    System.out.println("Your personal information: " + name + " of " + age + " years old."); 
}

}

输出：

C:\Temp\123431>java -classpath .;Main.class Main 
Hello, it is time to take a math test. 
First we need you to enter some information about yourself. 

Enter name: ttt 
Enter Age: 321 
Your personal information: ttt of 321 years old. 
C:\Temp\123431>java -classpath .;Main.class Main

答

的问题是，你要首先得到输入，然后你问了年龄。当你键入keyboard.nextInt（）时，它正在等待输入。所以，问题就在这里：

*int age = keyboard.nextInt(); 
    * System.out.println("Age: " + age); 
    *age = keyboard.nextInt();

我的建议是只删除第一keyboard.nextInt（）：例子：的System.out.println（ “\ n名称：” +姓名）; name = keyboard.nextLine（）;

System.out.println("Age: " + age); 
    final int age = keyboard.nextInt();

就是这样。请注意放置方法调用的位置，例如他们应该在你的println（）之后。

让用户输入创建对象

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