Python和子进程
问题描述:
这是为我正在处理的脚本。它应该为下面的循环运行一个.exe文件。 (顺便说一句,不确定它是否可见,但在('90','52.6223',...)中的el在循环之外,并与其他循环一起构成嵌套循环)我不确定排序是否正确或什么不是。另外,当.exe文件运行时,它会吐出一些东西,我需要在屏幕上打印某一行(因此,您看到AspecificLinfe = ...)。任何有用的答案都会很棒!Python和子进程
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
comstring = os.path.join('Path where .exe file is')
comstring = os.path.normpath(comstring)
comstring = '"' + comstring + '"'
comstringfull = comstring + ' -el ' + str(el) + ' -n ' + str(z)
print 'The python program is running this command with the shell:'
print comstring + '\n'
process = Popen(comstring,shell=True,stderr=STDOUT,stdout=PIPE)
outputstring = myprocesscommunicate()
print 'The command shell returned the following back to python:'
print outputstring[0]
AspecificLine=linecache.getline(' ??filename?? ', # ??
sys.stderr.write('az', 'el', 'AREA') # ??
答
使用shell=True
是错误的,因为这需要调用shell。
相反,这样做:
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
exepath = os.path.join('Path where .exe file is')
exepath = os.path.normpath(comstring)
cmd = [exepath, '-el', str(el), '-n', str(z)]
print 'The python program is running this command:'
print cmd
process = Popen(cmd, stderr=STDOUT, stdout=PIPE)
outputstring = process.communicate()[0]
print 'The command returned the following back to python:'
print outputstring
outputlist = outputstring.splitlines()
AspecificLine = outputlist[22] # get some specific line. 23?
print AspecificLine
也许你可能会补充说,如果你传递一个列表类似的对象subprocess.Popen它处理逃逸本身,如果你传递一个字符串,它不会发生。这将有助于理解你为什么在你的代码中使用了一个列表;) – DasIch 2009-06-01 22:17:53