如何在PHP中获取调用函数/方法的名称？

Question

我知道功能debug_backtrace，但我正在寻找一些准备使用像GetCallingMethodName()功能的实现？如果它也给方法的类也是完美的（如果它确实是一种方法）。

Answer 1

debug_backtrace()功能是知道这一点的唯一方法，如果你懒惰，那么你应该自己编码GetCallingMethodName()的另一个原因。 战斗懒惰！ ：D

Answer 2

我刚刚写了一个名为“get_caller”的版本，我希望它有帮助。我很懒惰。您可以运行从功能get_caller（），你不必像这样指定它：

get_caller(__FUNCTION__); 

下面是完整的脚本，包括离奇的测试用例：

<?php 

/* This function will return the name string of the function that called $function. To return the 
    caller of your function, either call get_caller(), or get_caller(__FUNCTION__). 
*/ 
function get_caller($function = NULL, $use_stack = NULL) { 
    if (is_array($use_stack)) { 
     // If a function stack has been provided, used that. 
     $stack = $use_stack; 
    } else { 
     // Otherwise create a fresh one. 
     $stack = debug_backtrace(); 
     echo "\nPrintout of Function Stack: \n\n"; 
     print_r($stack); 
     echo "\n"; 
    } 

    if ($function == NULL) { 
     // We need $function to be a function name to retrieve its caller. If it is omitted, then 
     // we need to first find what function called get_caller(), and substitute that as the 
     // default $function. Remember that invoking get_caller() recursively will add another 
     // instance of it to the function stack, so tell get_caller() to use the current stack. 
     $function = get_caller(__FUNCTION__, $stack); 
    } 

    if (is_string($function) && $function != "") { 
     // If we are given a function name as a string, go through the function stack and find 
     // it's caller. 
     for ($i = 0; $i < count($stack); $i++) { 
      $curr_function = $stack[$i]; 
      // Make sure that a caller exists, a function being called within the main script 
      // won't have a caller. 
      if ($curr_function["function"] == $function && ($i + 1) < count($stack)) { 
       return $stack[$i + 1]["function"]; 
      } 
     } 
    } 

    // At this stage, no caller has been found, bummer. 
    return ""; 
} 

// TEST CASE 

function woman() { 
    $caller = get_caller(); // No need for get_caller(__FUNCTION__) here 
    if ($caller != "") { 
     echo $caller , "() called " , __FUNCTION__ , "(). No surprises there.\n"; 
    } else { 
     echo "no-one called ", __FUNCTION__, "()\n"; 
    } 
} 

function man() { 
    // Call the woman. 
    woman(); 
} 

// Don't keep him waiting 
man(); 

// Try this to see what happens when there is no caller (function called from main script) 
//woman(); 

?> 

人（）调用调用get_caller（）的女士（）。 get_caller（）不知道是谁调用它，因为女人（）很谨慎，并没有告诉它，所以它会反复查找。然后它返回谁称为女人（）。并在浏览器的源代码模式下的打印输出显示功能栈：

Printout of Function Stack: 

Array 
(
    [0] => Array 
     (
      [file] => /Users/Aram/Development/Web/php/examples/get_caller.php 
      [line] => 46 
      [function] => get_caller 
      [args] => Array 
       (
       ) 

     ) 

    [1] => Array 
     (
      [file] => /Users/Aram/Development/Web/php/examples/get_caller.php 
      [line] => 56 
      [function] => woman 
      [args] => Array 
       (
       ) 

     ) 

    [2] => Array 
     (
      [file] => /Users/Aram/Development/Web/php/examples/get_caller.php 
      [line] => 60 
      [function] => man 
      [args] => Array 
       (
       ) 

     ) 

) 

man() called woman(). No surprises there. 

Answer 3

您也可以使用PHP异常所提供的信息，这是一个完美的解决方案：

 

function GetCallingMethodName(){ 
    $e = new Exception(); 
    $trace = $e->getTrace(); 
    //position 0 would be the line that called this function so we ignore it 
    $last_call = $trace[1]; 
    print_r($last_call); 
} 

function firstCall($a, $b){ 
    theCall($a, $b); 
} 

function theCall($a, $b){ 
    GetCallingMethodName(); 
} 

firstCall('lucia', 'php'); 

，你会得到这...（！瞧）

 
Array 
(
    [file] => /home/lufigueroa/Desktop/test.php 
    [line] => 12 
    [function] => theCall 
    [args] => Array 
     (
      [0] => lucia 
      [1] => php 
     ) 

) 

Answer 4

最简单的方法是：

echo debug_backtrace()[1]['function']; 

Answer 5

最好这个问题，我已经看到的答案是：

list(, $caller) = debug_backtrace(false); 

短和清洁

Answer 6

我需要的东西，只是列出调用类/方法（在Magento的项目工作）。

虽然debug_backtrace提供了大量实用的资讯，信息就喷涌出来Magento的安装量巨大（超过82000行！）因为我只关心调用函数和类，我工作这么小的解决方案达：

$callers=debug_backtrace(); 
foreach($callers as $call) { 
    echo "<br>" . $call['class'] . '->' . $call['function']; 
} 

Answer 7

对我来说debug_backtrace被击中我的内存限制，我想用这种生产，因为它们发生记录和电子邮件错误。

相反，我发现这个解决方案出色！

// Make a new exception at the point you want to trace, and trace it! 
$e = new Exception; 
var_dump($e->getTraceAsString()); 

// Outputs the following 
#2 /usr/share/php/PHPUnit/Framework/TestCase.php(626): SeriesHelperTest->setUp() 
#3 /usr/share/php/PHPUnit/Framework/TestResult.php(666): PHPUnit_Framework_TestCase->runBare() 
#4 /usr/share/php/PHPUnit/Framework/TestCase.php(576): PHPUnit_Framework_TestResult->run(Object(SeriesHelperTest)) 
#5 /usr/share/php/PHPUnit/Framework/TestSuite.php(757): PHPUnit_Framework_TestCase->run(Object(PHPUnit_Framework_TestResult)) 
#6 /usr/share/php/PHPUnit/Framework/TestSuite.php(733): PHPUnit_Framework_TestSuite->runTest(Object(SeriesHelperTest), Object(PHPUnit_Framework_TestResult)) 
#7 /usr/share/php/PHPUnit/TextUI/TestRunner.php(305): PHPUnit_Framework_TestSuite->run(Object(PHPUnit_Framework_TestResult), false, Array, Array, false) 
#8 /usr/share/php/PHPUnit/TextUI/Command.php(188): PHPUnit_TextUI_TestRunner->doRun(Object(PHPUnit_Framework_TestSuite), Array) 
#9 /usr/share/php/PHPUnit/TextUI/Command.php(129): PHPUnit_TextUI_Command->run(Array, true) 
#10 /usr/bin/phpunit(53): PHPUnit_TextUI_Command::main() 
#11 {main}" 

Answer 8

越来越父函数名的最简单的方法是：

$caller = next(debug_backtrace())['function']; 

Answer 9

我最喜欢的方式，在一条线！

debug_backtrace()[1]['function']; 

您可以使用它像这样：

echo 'The calling function: ' . debug_backtrace()[1]['function']; 

请注意，这只是与去年内释放的PHP版本兼容。但出于安全原因，最好让PHP始终保持最新状态。

Answer 10

由于PHP 5.4，你可以用

 $dbt=debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS,2); 
     $caller = isset($dbt[1]['function']) ? $dbt[1]['function'] : null; 

因为它忽略参数，返回只有最后2个回溯堆栈条目，且不会产生通知书这里其他的答案这不会浪费内存。