C#简单传递参数问题
问题描述:
我知道我听起来像一个糟糕的程序员现在 - 但我是新的,我不知道如何使用这个参考事物和传递参数,我的意思是我知道如何去做 - 但在同一时间 - 这是行不通的,我不知道为什么。C#简单传递参数问题
static void Main(string[] args) {
DealCard(ref card);
Console.WriteLine();
Console.ReadLine();
}
private static void DealCard(string card) {
string finalNum = "";
string finalSuite = "";
bool diffCard = false;
do {
Random cardPicker = new Random();
int cardSuite = cardPicker.Next(1, 5);
if (cardSuite == 1) {
finalSuite = "Hearts";
} else if (cardSuite == 2) {
finalSuite = "Spades";
} else if (cardSuite == 3) {
finalSuite = "Clubs";
} else if (cardSuite == 4) {
finalSuite = "Diamonds";
}
int cardNum = cardPicker.Next(1, 14);
if (cardNum == 1) {
finalNum = "Ace";
} else if (cardNum == 2) {
finalNum = "Two";
} else if (cardNum == 3) {
finalNum = "Thre";
} else if (cardNum == 4) {
finalNum = "Four";
} else if (cardNum == 5) {
finalNum = "Five";
} else if (cardNum == 6) {
finalNum = "Six";
} else if (cardNum == 7) {
finalNum = "Seven";
} else if (cardNum == 8) {
finalNum = "Eight";
} else if (cardNum == 9) {
finalNum = "Nine";
} else if (cardNum == 10) {
finalNum = "Ten";
} else if (cardNum == 11) {
finalNum = "Jack";
} else if (cardNum == 12) {
finalNum = "Queen";
} else if (cardNum == 13) {
finalNum = "King";
}
string newCard = finalNum + " of " + finalSuite;
if (newCard != card) {
card = finalNum + " of " + finalSuite;
diffCard = true;
} else {
}
card = newCard;
} while (diffCard == false);
}
是的我知道大量'如果'是一个眼睛。 是的,我知道我可以在不到一半的条件下完成这项工作。 是的,我知道这是一个简单的问题。 是的我知道我很糟糕,但我想虚心请求任何人帮助我停止失去头发。
答
您必须声明你的方法是这样的:
private static void DealCard(ref string card)
基本方法必须接受ref参数。
这里是文档,以支持该回答:
答
您的代码可以是这样的
public class Program
{
public static void Main(string[] args) {
string card = "";
DealCard(ref card);
}
private static void DealCard(ref string card)
{
string finalNum = "";
string finalSuite = "";
bool diffCard = false;
do {
Random cardPicker = new Random();
int cardSuite = cardPicker.Next(1, 5);
string[] suite = new String[]{"Hearts","Spades", "Clubs", "Diaminds"};
int cardNum = cardPicker.Next(1, 3);
string[] numbers = new String[]{"one","two","three", "four"};
string newCard = numbers[cardNum] + " of " + suite[cardSuite];
if (newCard != card) {
card = finalNum + " of " + finalSuite;
diffCard = true;
} else {
}
card = newCard;
Console.WriteLine(newCard);
} while (diffCard == false);
}
}
你不需要这样的:'DealCard(REF卡) ;'因为这会起作用:'DealCard(card);'但是,如果你有意使用'ref'并且你确切地知道为什么,那是不同的情况。 – CodingYoshi
我知道你特别要求不要因为大量的失败而失去头脑。但是,我只想为您提供简单的替代解决方案:使用字典。键将是数字,值字符串。然后,您可以用cardValuesDict [cardNumber] – netchkin
替换整个卡片,然后在调用“DealCard”之前声明'var card =“”;“。 – aaron