有一个字符数组的内容为:“student a am i”, 请将数组的内容改为"i am a student". 要求： 不能使用库函数。
#include<stdio.h>
#include<stdlib.h>
int Strlen(char* str) {
if (*str == '\0') {
return 0;
}
else {
return Strlen(str + 1) + 1;
}
}
void fun(char str[],int L) {
int ret = 0;
for (int i = 0; i < L / 2; ++i) {
str[i] = str[i] ^ str[L - 1 - i];
str[L - 1 - i] = str[i] ^ str[L - 1 - i];
str[i] = str[i] ^ str[L - 1 - i];
}
printf("//中间值为：%s\n", str);
for (int i = 0; i <= L; ++i) {
if (str[i] == ' '|| str[i] == '\0') {
for (int j = ret, m = 1; m <= (i - ret) / 2; ++j, ++m) {
str[j] = str[j] ^ str[i - m];
str[i - m] = str[j] ^ str[i - m];
str[j] = str[j] ^ str[i - m];
}
ret = i + 1;
}
}
}
void main() {
char str[] = "student am I";
printf("原字符串为:%s\n", str);
int L = Strlen(str);
fun(str, L);
printf("转换完成后:%s\n", str);
system("pause");
}
