【leetcode】---数组题目【python】
26.Remove duplicate from Sorted Array
思路:题目不允许开辟新空间,且数组排好序。若nums[i]==nums[index-1],增加i去避免复制。当nums[i]!=nums[index-1],此时进行复制,且让index+1,重复操作直至i达到len(nums)
class Solution:
def removeDuplicates(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if len(nums)==0:
return 0
index = 1
for i in range(1,len(nums)):
if nums[i] != nums[index-1]: #找出与nums[index-1]不相等的数组下标i
nums[index]=nums[i] #不同值赋值给num[index]
index += 1 #此处index+1便于下次赋值,恰好为不重复数组长度
return index
80.Remove Depulicates from Sorted Array II
思路:同上,重点在于改成判断nums[i]与nums[index-2]
class Solution:
def removeDuplicates(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if len(nums)<=2:
return len(nums)
index = 2
for i in range(2,len(nums)):
if nums[i]!=nums[index-2]:
nums[index] = nums[i]
index +=1
return index
思路一:暴力**
思路二:先排序
思路三:去掉重复元素,在分别从两边扩散