python 列表矩阵的每一行求和
第一种方法用for循环
import numpy as np
num = np.arange(16).reshape(4,4)+1
a =[]
for j in range(4):
sum=0
for k in range(4):
sum+=num[j][k]
a.append(sum)
print(a)
第二种用矩阵：
import numpy as np
num = np.arange(16).reshape(4,4)+1
num1= np.array([1,1,1,1]).reshape(4,1)
a =np.mat(num) * np.mat(num1)