内容:就是有两个数A,B 能找到一组数(x,y)使得Ax+B*y=gcd(A,B)

一、代码

#include<iostream>
#include<string>
#include<stdio.h>
#include<string.h>
using namespace std;
int exgcd(int a,int b,int &x,int &y)
{
    if(b==0)
    {
        x=1;
        y=0;
        return a;
    }
    int r=exgcd(b,a%b,x,y);
    int t=x;
    x=y;
    y=t-(a/b)*x;
    return r;
}
int main(int argc,char *argv)
{
  int a,b,x,y;
  cout<<"please input the first data  A"<<endl;
  cin>>a;
  cout<<"please input the first data  B"<<endl;
  cin>>b;
  cout<<exgcd(a,b,x,y);
  cout<<"   "<<x<<"    "<<y<<endl;
}

二、结果