JavaScript编程黑科技,装逼指南,高逼格代码,让你惊叹不已
JavaScript是一门很吊的语言,我可能学了假的JavaScript……
本文秉承着:你看不懂是你SB,我写的代码就要牛逼。
1、单行写一个评级组件
"★★★★★☆☆☆☆☆".slice(5 - rate, 10 - rate);定义一个变量rate是1到5的值,然后执行上面代码,看图
才发现插件什么的都弱爆了
来源:来自知乎用户蜗牛老湿的回答
2、如何装逼用代码骂别人SB
(!(~+[])+{})[--[~+""][+[]]*[~+[]] +~~!+[]]+({}+[])[[~!+[]]*~+[]]
了解为什么请移步:一行能装逼的JavaScript代码
3、如何用代码优雅的证明自己NB
这个牛逼了
console.log(([][[]]+[])[+!![]]+([]+{})[!+[]+!![]])
4、JavaScript 错误处理的方式的正确姿势
�� �� �� ,舅服你
try{ something} catch(e) { window.location.href="http://stackoverflow.com/search?q=[js]+"+e.message;}
5、从一行代码里面学点JS
[].forEach.call($$("*"),function(a){
a.style.outline="1px solid #"+(~~(Math.random()*(1<<24))).toString(16)})
翻译成正常语言就是这样的
Array.prototype.forEach.call(document.querySelectorAll('*'), dom=>dom.style.outline=`1px solid #${parseInt(Math.random() *
Math.pow(2,24)).toString(16)}`)
接下来在浏览器控制看看:something magic happens
具体分析请参见这篇文章:从一行代码里面学点Java
6、论如何优雅的取随机字符串
Math.random().toString(16).substring(2) //13位Math.random().toString(36).substring(2) //11位
7、(10)["toString"]() === "10"
解析请移步:js奇淫技巧1
8、匿名函数自执行
这么多写法你选择哪一种?我选择死亡。
( function() {}() );( function() {} )();[ function() {}() ];~function() {}();!function() {}();+function() {}();-function() {}();deletefunction() {}();typeoffunction() {}();voidfunction() {}();newfunction() {}();newfunction() {};varf=function() {}();1, function() {}();1^function() {}();1>function() {}();//...
9、另外一种undefined
从来不需要声明一个变量的值是undefined,因为JavaScript会自动把一个未赋值的变量置为undefined。所有如果你在代码里这么写,会被鄙视的
vardata =undefined;
但是如果你就是强迫症发作,一定要再声明一个暂时没有值的变量的时候赋上一个undefined。那你可以考虑这么做:
vardata =void0; //undefined
void在JavaScript中是一个操作符,对传入的操作不执行并且返回undefined。void后面可以跟()来用,例如void(0),看起来是不是很熟悉?没错,在HTML里阻止带href的默认点击操作时,都喜欢把href写成javascript:void(0),实际上也是依靠void操作不执行的意思。
当然,除了出于装逼的原因外,实际用途上不太赞成使用void,因为void的出现是为了兼容早起ECMA标准中没有undefined属性。void 0的写法让代码晦涩难懂。
10、论如何优雅的取整
vara =~~2.33varb=2.33|0varc=2.33>>0
11、如何优雅的实现金钱格式化:1234567890 --> 1,234,567,890
用正则魔法实现:
vartest1 ='1234567890'varformat =test1.replace(/B(?=(d{3})+(?!d))/g, ',')console.log(format)//1,234,567,890
非正则的优雅实现:
functionformatCash(str) { returnstr.split('').reverse().reduce((prev, next, index) =>{ return((index%3) ?next :(next +',')) +prev })}console.log(formatCash('1234567890')) //1,234,567,890
12、这个我服,还有这个你很机智
我服
while(1) { alert('牛逼你把我关了啊')}
你很机智,好一个障眼法
清除缓存: <ahref="javascript:alert('清除成功');">清除缓存</a>
13、逗号运算符
vara =0; varb =( a++, 99); console.log(a); //1console.log(b); //99
14、论如何最佳的让两个整数交换数值
常规办法:
vara=1,b=2;a +=b;b =a -b;a -=b;
缺点也很明显,整型数据溢出,对于32位字符最大表示数字是2147483647,如果是2147483645和2147483646交换就失败了。
黑科技办法:
a ^=b;b ^=a;a ^=b;
哈哈 �� ,看不懂的童鞋建议去补习一下C语言的位操作,我就不去复习了,以前学嵌入式时候学的位操作都忘了
15、实现标准JSON的深拷贝
vara ={ a:1, b:{ c:1, d:2}}varb=JSON.parse(JSON.stringify(a))
不考虑IE的情况下,标准JSON格式的对象蛮实用,不过对于undefined和function的会忽略掉。
16、不用Number、parseInt和parseFloat和方法把"1"字符串转换成数字
哈哈,不准用强制类型转换,那么就想到了强大了隐式转换
vara =1+a
17、如何装逼的写出"hello world!"
滚动条很长哦 ��
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居然能运行,牛逼的隐式转换
18、parseInt(0.0000008) === 8
19、++[[]][+[]]+[+[]] == 10
强大的隐式转换,23333
20、0.1 + 0.2 == 0.3
0.1 +0.2 == 0.3 竟然是不成立的。。。。所以这就是为什么数据库存储对于货币的最小单位都是分。
简单说,0.1和0.2的二进制浮点表示都不是精确的,所以相加后不是0.3,接近(不等于)
0.30000000000000004。
所以,比较数字时,应该有个宽容值。ES6中这个宽容值被预定义了:Number.EPSILON。
21、最短的代码实现数组去重
[...newSet([1, "1", 2, 1, 1, 3])]
前不久面试阿里就问了这道题,哈哈,所以也写上一下
22、用最短的代码实现一个长度为m(6)且值都n(8)的数组
Array(6).fill(8)
这个够短了吧,好像是当初哪里看到的一个面试题,就自己想到了ES6的一些API
23、短路表达式
条件判断
vara =b &&1//相当于if(b) { a =1} else{ a =b}vara =b ||1//相当于if(b) { a =b} else{ a =1}
24、Java版迷宫
逃出迷宫,2333
25、取出一个数组中的最大值和最小值
varnumbers =[5, 458, 120, -215, 228, 400, 122205, -85411]; varmaxInNumbers=Math.max.apply(Math, numbers); varminInNumbers =Math.min.apply(Math, numbers);
26、将argruments对象转换成数组
varargArray =Array.prototype.slice.call(arguments);或者ES6:varargArray=Array.from(arguments)
27、java高逼格之Function构造函数
很多Java教程都告诉我们,不要直接用内置对象的构造函数来创建基本变量,例如var arr = new Array(2); 的写法就应该用var arr = [1, 2];的写法来取代。
但是,Function构造函数(注意是大写的Function)有点特别。Function构造函数接受的参数中,第一个是要传入的参数名,第二个是函数内的代码(用字符串来表示)。
varf =newFunction('a', 'alert(a)');f('jawil'); //将会弹出窗口显示jawil
这种方式可以根据传入字符串内容来创建一个函数 是不是高大上?!
28、从一个数组中找到一个数,O(n)的算法,找不到就返回 null。
正常的版本:
functionfind(x, y) { for( leti =0; i <x.length; i++) { if( x[i] ==y ) returni; } returnnull;} letarr =[0,1,2,3,4,5]console.log(find(arr, 2))console.log(find(arr, 8))
结果到了函数式成了下面这个样子(好像上面的那些代码在下面若影若现,不过又有点不太一样,为了消掉if语言,让其看上去更像一个表达式,动用了 ? 号表达式):
//函数式的版本constfind=( f=>f(f) ) ( f=>(next=>(x, y, i=0) =>( i >=x.length) ?null:( x[i] ==y ) ?i:next(x, y, i+1))((...args) =>(f(f))(...args))) letarr =[0,1,2,3,4,5]console.log(find(arr,2))console.log(find(arr, 8))
如何读懂并写出装逼的函数式代码
最后奉劝大家一句:莫装逼、白了少年头,2333。。。