MySQL查询帮助需要
问题描述:
我试图构建复杂的MySQL查询,但其返回错误结果...
SELECT b.name AS batch_name, b.id AS batch_id,
COUNT(DISTINCT s.id) AS total_students,
COALESCE(sum(s.open_bal), 0) AS open_balance,
sum(COALESCE(i.reg_fee,0) + COALESCE(i.tut_fee,0) + COALESCE(i.other_fee,0)) AS gross_fee,
sum(COALESCE(i.discount,0)) AS discount,
COALESCE(sum(s.open_bal), 0) + sum(COALESCE(i.reg_fee,0) + COALESCE(i.tut_fee,0) + COALESCE(i.other_fee,0)) - sum(COALESCE(i.discount,0)) AS net_payable,
sum(COALESCE(r.reg_fee,0) + COALESCE(r.tut_fee,0) + COALESCE(r.other_fee,0)) AS net_recieved,
(COALESCE(sum(s.open_bal), 0) + sum(COALESCE(i.reg_fee,0) + COALESCE(i.tut_fee,0) + COALESCE(i.other_fee,0)) - sum(COALESCE(i.discount,0))) - (sum(COALESCE(r.reg_fee,0) + COALESCE(r.tut_fee,0) + COALESCE(r.other_fee,0))) AS balance_due
FROM batches b
LEFT JOIN students s on s.batch = b.id
LEFT JOIN invoices i on i.student_id = s.id
LEFT JOIN recipts r on r.student_id = s.id
WHERE s.inactive = 0
GROUP BY b.name, b.id;
我是因为sum(open_bal)结果是错误的,所以做错了。
样品结果...
| batch_name | total_students | open_bal | gross_fee | discount | net_payable | net_recieved | due_balance |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
| MS | 6 | 10000 | 0 | 0 | 10000 | 101000 | -91000 |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
以上结果是错误的,请检查下面的表结构
学生表
| id | open_bal | batch |
+-----+----------+-------+
| 44 | -16000 | 9 |
+-----+----------+-------+
| 182 | 9000 | 9 |
+-----+----------+-------+
| 184 | -36000 | 9 |
+-----+----------+-------+
| 185 | 19000 | 9 |
+-----+----------+-------+
| 186 | 9000 | 9 |
+-----+----------+-------+
| 187 | 4000 | 9 |
+-----+----------+-------+
发票表
| id | student_id | reg_fee | tut_fee | other_fee | net_payable | discount |
+------+------------+---------+---------+-----------+-------------+----------+
| | | | | | | |
+------+------------+---------+---------+-----------+-------------+----------+
没有发票可用于以上学生ID。
Recipts表
| id | student_id | reg_fee | tut_fee | other_fee | status |
+------+------------+---------+---------+-----------+------------+
| 8 | 44 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 277 | 44 | 0 | 50000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 26 | 182 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 424 | 182 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 468 | 182 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 36 | 185 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 697 | 185 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 66 | 187 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
使用上面的SQL查询和表格预期结果...
| batch_name | total_students | open_bal | gross_fee | discount | net_payable | net_recieved | due_balance |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
| MS | 6 | -11000 | 0 | 0 | 10000 | 101000 | -112000 |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
请检查并回复,谢谢。
答
您必须将student_id添加到GROUP BY表达式中。
您正在创建多个外连接,这意味着所有数据将用于查询中,但收据表中的某些学生也有多行,因此它们的金额会被复制(因为会有与该s.id几行)。
采取以下加入一看:
r.id s.id open_bal
--------------------------
8 | 44 | -16000
277 | 44 | -16000
26 | 182 | 9000
424 | 182 | 9000
468 | 182 | 9000
36 | 185 | 19000
697 | 185 | 19000
66 | 187 | 4000
null | 184 | -36000
null | 186 | 9000
概括起来,你会被前面的问题(以上)的同一用户获得10万
+0
可以请你发布sql查询吗?如果我写GROUP BY r.student_id,b.name,b.id然后我得到的所有数据由r.id分组而不是b.name – seoppc
精确转贴。请不要转发您近期询问的问题,@seoppc。谢谢。 –
@Jordan是的,我创造了新的问题。我真的很困惑,请帮助。 – seoppc