MySQL的snafoo与GROUP_CONCAT
问题描述:
SELECT DISTINCT HEX(group_uuid) AS hexid
FROM schema.table
>9B3D8DE01E1E049DA9F17D42B324AA66
>CDF112D740CE14EA08CA90E3C937DE8D
为做到这一点
SELECT GROUP_CONCAT('\'', HEX(group_uuid), '\' ') AS hexid
FROM schema.table
>'9B3D8DE01E1E049DA9F17D42B324AA66','9B3D8DE01E1E049DA9F17D42B324AA66' [etc...]
这
SELECT GROUP_CONCAT(DISTINCT HEX(group_uuid) SEPARATOR '\' ') AS hexid
FROM schema.table
>9B3D8DE01E1E049DA9F17D42B324AA66' CDF112D740CE14EA08CA90E3C937DE8D
这一点,但是,
SELECT GROUP_CONCAT('\'', DISTINCT HEX(group_uuid), '\' ') AS hexid
FROM schema.table
Error Code: 1064. You have an error in your SQL syntax; INSERT COIN
没有。
是否有某种'PREFIX'关键字可以被替换或我应该遵循的其他语法?
答
您是否在寻找
GROUP_CONCAT(DISTINCT CONCAT('\'',HEX(group_uuid),'\'') SEPARATOR ' ')
千恩万谢! – Greg 2012-07-21 12:31:28