编译错误MS Access SQL
我得到一个编译错误:“参数不是可选的” 基本上在这段代码中,我试图围绕表格样式自动分配。当代码被调用时,它开始于AssignNullProjects()
,当我得到的错误,GetNextAssignee
是亮点中的一部分" & GetNextAssignee & "
编译错误MS Access SQL
我真的不知道如何解决它,这是我下面全码:
Public Function AssignNullProjects() As Long
Dim db As dao.Database
Dim rs As dao.Recordset
Dim strSQL As String
Set db = CurrentDb
strSQL = "SELECT CFRRRID, [program], [language] FROM CFRRR WHERE assignedto Is Null"
Set rs = db.OpenRecordset(strSQL, dbOpenDynaset)
If Not rs.BOF And Not rs.EOF Then
While Not rs.EOF
strSQL = "UPDATE CFRRR SET assignedto = " & GetNextAssignee & ", assignedby = " & [Forms]![CFRRR]![assignedby] & ", Dateassigned = #" & Now & "#, actiondate = #" & Now & "#, Workername = " & _
[Forms]![CFRRR]![assignedto] & ", WorkerID = " & [Forms]![CFRRR]![assignedto] & " WHERE CFRRRID = " & rs!CFRRRID
db.Execute strSQL, dbFailOnError
rs.MoveNext
Wend
End If
rs.Close
db.Close
Set rs = Nothing
Set db = Nothing
End Function
Public Function GetNextAssignee(program As String, Language As String) As Long
' Returns UserID as a Long Integer with the lowest [TS] value,
' and updates same [TS] by incremented with 1.
Dim db As dao.Database
Dim rs As dao.Recordset
Dim strSQL As String
Set db = CurrentDb
strSQL = "SELECT TOP 1 WorkerID FROM attendance WHERE [Programs] LIKE '*" & program & "*' AND [Language] = '" & Language & "' AND [Status] = '" & Available & "' ORDER BY TS ASC"
Set rs = db.OpenRecordset(strSQL, dbOpenDynaset)
If Not rs.BOF And Not rs.EOF Then
'Found next assignee, update date/time stamp
' strSQL = "UPDATE tblUser SET TS = " & DMax("[TS]", tblUser) + 1 & " WHERE [WorkerID]= " & rs!workerid
strSQL = "UPDATE attendance SET TS = " & DMax("[TS]", "attendance") + 1 & " WHERE [WorkerID]= " & rs!workerid
db.Execute strSQL, dbFailOnError
GetNextAssignee = rs!workerid
Else
'Field TS has NO VALUE FOR ALL RECORDS!
'Code calling this function should check for a return of 0 indicating an error.
GetNextAssignee = 0
End If
rs.Close
db.Close
Set rs = Nothing
Set db = Nothing
End Function
当你调用这个函数,你必须提供2个参数(字符串值):
Public Function GetNextAssignee(program As String, Language As String) As Long
但构建UPDATE
语句时,你叫塔没有提供所需的参数t的函数:
strSQL = "UPDATE CFRRR SET assignedto = " & GetNextAssignee & ", assignedby = "
这样进出抱怨那些(串)参数是不可选的 - 你必须提供他们。当你给函数像这样2串代码应该编译...
strSQL = "UPDATE CFRRR SET assignedto = " & GetNextAssignee("foo", "bar") & ", assignedby = "
尽管代码将与这些字符串编译,功能可能不会返回你所需要的结果。因此用实际值代替foo和bar。
我是否按照功能键入? ''&GetNextAssignee(程序为字符串,语言为字符串)As Long&“'但我收到一个错误,说明列表分隔符或)并且'As'突出显示。 – Lilly
伟大的伎俩,现在我得到一个错误的下半部分,说太少的参数:期望2.'strSQL =“选择TOP1 WorkerID从出席在哪里[程序]像'*”&程序&“* '和[语言] =''和语言&''和[状态] =“&(”可用“)和”按顺序ASC“ Set rs = db.OpenRecordset(strSQL,dbOpenDynaset)''''虽然。 – Lilly
是的,这是一个不同的问题,所以一个新的问题是要走的路。当你写这个问题时,当你遇到新的错误时,请粘贴“Debug.Print strSQL”的输出。最好向我们展示实际的失败声明,而不仅仅是创建声明的代码。 – HansUp
'GetNextAssignee'显然需要两个参数('program'和'Language'),如声明中所示;你的调用代码并不提供'&GetAssignee&')。你还希望发生什么? “为了通过邮递服务送达,你的信件需要两件事:一个送货地址和一张邮资充足的邮票,你们两个都没有提供,我们无法完成你寄送这封信的请求。” –