5位数=2*四位数,9个数字互不相同

代码


#include<stdio.h>
#include<stdlib.h>
int main()
{
	int a, b, c, d,  i, j, F = 0, E = 0, E1 = 0, t;
	for (a = 5; a <= 9; a++)
	{
		for (b = 0; b <= 9; b++)
		{
			for (c = 0; c <= 9; c++)
			{
				for (d = 0; d <= 9; d++)
				{
					int A[10] = { 0 };
					t = 1;
					A[0] = a; A[1] = b; A[2] = c; A[3] = d;
					F = a * 1000 + b * 100 + c * 10 + d;
					E = F * 2;
					E1 = E;
					for (i = 4; i < 9; i++)
					{
						A[i] = E1 % 10;
						E1 = E1 / 10;
					}
					for (i = 0; i <8; i++)
					{
						for (j = i + 1; j < 9; j++)
							if (A[i] == A[j])
							{
								t = 0;
								break;
							}
					}
					if (t == 1)
					{
						printf("2*%d=%d\n", F, 2 * F);
					}
				}
			}
		}
	}
	system("pause");
	return 0;
}

运行结果

5位数=2*四位数,9个数字互不相同