函数返回一个表

Question

这里我有一个函数需要'COMMA SEPARATED STRING'并返回一个流水线表。

create or replace 
    FUNCTION parse_comma_delimited 
    (
    iv_list IN VARCHAR2, 
    v_delimiter IN VARCHAR2 DEFAULT ',' 
    ) 
    RETURN parse_comma_delimited_pkg.tt_v_tablevalues_type PIPELINED 
    AS 
     v_list VARCHAR2(8000) := iv_list; 
     v_item VARCHAR2(255); 
     v_temp SYS_REFCURSOR; 
     v_temp_1 TT_V_TABLEVALUES%ROWTYPE; 
    BEGIN 
    WHILE (LENGTHB(v_list) > 0) 
    LOOP 
    BEGIN 
    IF INSTR(v_list, v_delimiter) > 0 THEN 
    BEGIN 
     v_item := SUBSTR(v_list, 1, (INSTR(v_list, v_delimiter) - 1)) ; 
     v_list := SUBSTR(v_list, (INSTR(v_list, v_delimiter) 
     || LENGTHB(v_delimiter)), LENGTHB(v_list)) ; 
    END; 
    ELSE 
    BEGIN 
     v_item := v_list ; 
     v_list := NULL ; 
    END; 
    END IF; 

    INSERT INTO tt_v_tablevalues (item) VALUES (v_item); 
    END; 
END LOOP; 
OPEN v_temp FOR 
    SELECT * 
    FROM tt_v_tablevalues; 
    LOOP 
    FETCH v_temp INTO v_temp_1; 
    EXIT WHEN v_temp%NOTFOUND; 
    PIPE ROW (v_temp_1); 
    END LOOP; 
END; 

但是，当我调用函数时，它只能重新调整一行。

INSERT INTO SRC_PK_INSERT (pk_key) 
SELECT * 
FROM TABLE(parse_comma_delimited(( 
SELECT * 
FROM SRC_PK_INSERT 
WHERE RULE_NAME = 'RULES' 
))); 

Answer 1

使用流水线函数填充row_type，然后调用管道行。

在这里看到的文档：http://docs.oracle.com/cd/B28359_01/appdev.111/b28425/pipe_paral_tbl.htm#CHDJEGHC

从文档实例：

CREATE FUNCTION StockPivot(p refcur_pkg.refcur_t) RETURN TickerTypeSet 
PIPELINED IS 
    out_rec TickerType := TickerType(NULL,NULL,NULL); 
    in_rec p%ROWTYPE; 
BEGIN 
    LOOP 
    FETCH p INTO in_rec; 
    EXIT WHEN p%NOTFOUND; 
    -- first row 
    out_rec.ticker := in_rec.Ticker; 
    out_rec.PriceType := 'O'; 
    out_rec.price := in_rec.OpenPrice; 
    PIPE ROW(out_rec); 
    -- second row 
    out_rec.PriceType := 'C'; 
    out_rec.Price := in_rec.ClosePrice; 
    PIPE ROW(out_rec); 
    END LOOP; 
    CLOSE p; 
    RETURN; 
END; 
/